提供两种思路解决去掉重复的数字:

 1)添加一个数组,但是长度无法确定,记录没有重复的值

 2)添加一个数组,用于记录原数组中存在的主,再添加一个数组,可以确定数组的长度,用于存放原数组的值.

public class TextDelRepeat {
	/**
	 * 去掉数组中重复的数字
	 * @param src
	 * @return
	 */
	public static int[] changeMethodOne(int src[]) {
		int length = src.length;
		int[] taget = new int[length];
		
		int index = 0;
		taget[0] = src[0];
		for(int i = 1; i < length; i++) {
			if(taget[index] != src[i]) {
				index ++;
				taget[index] = src[i];
			}
		}
		return taget;
	}
	/**
	 * 去掉数组中重复的数字
	 * @param src
	 * @return
	 */
	public static int[] changeMethodTwo(int src[]) {
		int length = src.length;
		int[] tagetIndex = new int[length];
		int tagetLenght = length;
		for (int i = 0; i < length; i++) {
			tagetIndex[i] = 0;
		}
		for(int i = 1; i < length; i++) {
			if(src[i] == src[i-1]) {
				tagetIndex[i] = 1;
				tagetLenght --;
			}
		}
		
		//声明数组,长度传入数组长度-重复数字个数
		int[] target = new int[tagetLenght];
		int index = 0;
		for(int i = 0; i < length; i++) {
			if(tagetIndex[i] == 0) {
				target[index++] = src[i];
			}
		}
		return target;
	}
	
	public static void main(String[] args) {
		int[] a = {1, 1, 1, 2, 3, 4, 5, 6, 9, 9, 12, 53};
		int[] b = changeMethodOne(a);
		System.out.println("(1)");
		for(int i = 0; i < b.length; i++) {
			System.out.print(b[i] + " ");
		}
		System.out.println();
		System.out.println("(2)");
		int[] c = changeMethodTwo(a);
		for(int i = 0; i < c.length; i++) {
			System.out.print(c[i] + " ");
		}
	}
}