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[LeetCode]185. 部门工资前三高的所有员工

部门工资前三高的所有员工

Employee 表包含所有员工信息,每个员工有其对应的工号 Id,姓名 Name,工资 Salary 和部门编号 DepartmentId 。

IdNameSalaryDepartmentId
1Joe850001
2Henry800002
3Sam600002
4Max900001
5Janet690001
6Randy850001
7Will700001

Department 表包含公司所有部门的信息。

IdName
1IT
2Sales

编写一个 SQL 查询,找出每个部门获得前三高工资的所有员工。例如,根据上述给定的表,查询结果应返回:

DepartmentEmployeeSalary
ITMax90000
ITRandy85000
ITJoe85000
ITWill70000
SalesHenry80000
SalesSam60000

解释:

IT 部门中,Max 获得了最高的工资,Randy 和 Joe 都拿到了第二高的工资,Will 的工资排第三。销售部门(Sales)只有两名员工,Henry 的工资最高,Sam 的工资排第二。

思路

1.先建表造数据:

Create table If Not Exists Employee (Id int, Name varchar(255), Salary int, DepartmentId int)
Create table If Not Exists Department (Id int, Name varchar(255))
Truncate table Employee
insert into Employee (Id, Name, Salary, DepartmentId) values ('1', 'Joe', '85000', '1')
insert into Employee (Id, Name, Salary, DepartmentId) values ('2', 'Henry', '80000', '2')
insert into Employee (Id, Name, Salary, DepartmentId) values ('3', 'Sam', '60000', '2')
insert into Employee (Id, Name, Salary, DepartmentId) values ('4', 'Max', '90000', '1')
insert into Employee (Id, Name, Salary, DepartmentId) values ('5', 'Janet', '69000', '1')
insert into Employee (Id, Name, Salary, DepartmentId) values ('6', 'Randy', '85000', '1')
insert into Employee (Id, Name, Salary, DepartmentId) values ('7', 'Will', '70000', '1')
Truncate table Department
insert into Department (Id, Name) values ('1', 'IT')
insert into Department (Id, Name) values ('2', 'Sales')

先查询到部门名字、员工名字、薪水,判断条件为不超过3个工资比这些值大的值。

SELECT
	d.NAME AS Department,
	e1.NAME AS Employee,
	e1.Salary 
FROM
	Employee e1
	JOIN Department d ON e1.DepartmentId = d.Id 
WHERE
		3 > (
				SELECT
						COUNT( DISTINCT e2.Salary ) 
				FROM
						Employee e2 
				WHERE
						e2.Salary > e1.Salary 
				AND e1.DepartmentId = e2.DepartmentId 
				)
;