1、最简单的内置format函数:
>>> format(1234567890,',')
'1,234,567,890'
2、正则表达式:
import re
def formatNum(num):
num=str(num)
pattern=r'(\d+)(\d{3})((,\d{3})*)'
while True:
num,count=re.subn(pattern,r'\1,\2\3',num)
if count==0:
break
return num
if __name__=='__main__':
print formatNum(1234455)
3、最笨的倒置后遍历过三位加逗号:
def formatNum(num):
num=str(num)
result=''
count=0
for i in num[::-1]:
count+=1
result+=i
if count%3==0:
result+=','
return result[::-1].strip(',')
if __name__=='__main__':
print formatNum(123445)