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linux go守护进程,Go到目前还没有解决成为守护进程(Daemonize)的问题吧?各位是怎么解决的?...

这是StackOverFlow上写的,

还有官网的

我自己试图抄了一段代码,可以工作,但问题在于我在子进程里面调用了一下time.Sleep后,子进程就不动了。用strace看到子进程卡在epoll调用上。

请问大家是怎么解决这个问题的?就用很土的nohup ./go-exec &这种shell来实现吗?

package main

import (

"log"

"os"

"runtime"

"errors"

"syscall"

)

func daemon(chdir bool, closeStd bool) (err error){

var ret, ret2 uintptr

var er syscall.Errno

darwin := runtime.GOOS == "darwin"

// already a daemon

if syscall.Getppid() == 1 {

return

}

// fork off the parent process

ret, ret2, er = syscall.RawSyscall(syscall.SYS_FORK, 0, 0, 0)

if er != 0 {

err = errors.New("fork fail")

return

}

// failure

if ret2 < 0 {

err = errors.New("fork fail")

os.Exit(-1)

}

// handle exception for darwin

if darwin && ret2 == 1 {

ret = 0

}

// if we got a good PID, then we call exit the parent process.

if ret > 0 {

os.Exit(0)

}

/* Change the file mode mask */

_ = syscall.Umask(0)

// create a new SID for the child process

s_ret, s_errno := syscall.Setsid()

if s_errno != nil {

log.Printf("Error: syscall.Setsid errno: %d", s_errno)

}

if s_ret < 0 {

err = errors.New("setsid fail")

return

}

if chdir {

os.Chdir("/")

}

if closeStd {

f, e := os.OpenFile("/dev/null", os.O_RDWR, 0)

if e == nil {

fd := f.Fd()

syscall.Dup2(int(fd), int(os.Stdin.Fd()))

syscall.Dup2(int(fd), int(os.Stdout.Fd()))

syscall.Dup2(int(fd), int(os.Stderr.Fd()))

}

}

return

}

;