python 内部自带大整数运算能力，整数运算不会溢出，只要内存足够，就oK

下面的例子演示了两个32位整数加法的情况(通过位运算实现)，为了模拟溢出的效果，必须人工的进行位运算，~运算符除了求反，还是二进制的补运算符，运算过后的二进制数字按照补码解释，例如 ~(0011 1100) = (1100 0011) = -61

def getSum(a, b):

"""

:type a: int

:type b: int

:rtype: int

"""

MAX = 0X7fffffff

MIN = 0X80000000

while b != 0 :

a,b = a^b,(a&b)<<1

print(" a = {0:b},b = {1:b}".format(a,b))

return a

def getSum_(a, b):

"""

:type a: int

:type b: int

:rtype: int

"""

MAX = 0x7FFFFFFF

MIN = 0x80000000

mask = 0xFFFFFFFF

while b != 0:

a, b = (a ^ b) & mask, ((a & b) << 1) & mask

print(type(a))

print(" a = {0:b},b = {1:b}".format(a,b))

return a if a <= MAX else ~(a^mask)

print(getSum_(-1,-1))

print(getSum(-1,1))

补充：python 循环内部添加多个条件判断会出现越界

1.循环遍历数组是,想添加条件修改时,只删除第一个

# -*- coding: utf-8 -*-

a=[11,22,33,44,55]

for i in a:

if i == 11 or i ==22:

a.remove(i)

for i in a:

print(i)

'''

33

55

[Finished in 0.1s]

'''

2.应该引入被删除为一个数组

# -*- coding: utf-8 -*-

a=[11,22,33,44,55]

b=[]

for i in a:

if i == 11 or i ==22:

b.append(i)

for i in b:

a.remove(i)

for i in a:

print(i)

'''

33

44

55

[Finished in 0.1s]

'''

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本文标题: python 整数越界问题详解

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