Bitwise AND of Numbers Range

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.

For example, given the range [5, 7], you should return 4.

public class Solution {
    public int rangeBitwiseAnd(int m, int n) {
        if(m == 0)
            return 0;
        int result = 0;
        int temp = m;
        int bits[] = new int[32];
        for(int i = 0; i < 32; i++){
            bits[i] = (temp & 1);
            temp >>>= 1;
        }
        
        int carry = (n - m);
        for(int i = 0; i < 32; i++){
            carry = (carry + bits[i]) / 2;
            if(bits[i] + carry > 1)
                bits[i] = 0;
        }
        
        for(int i = 31; i >=0; i--){
            result <<= 1;
            result += bits[i];
        }//for
        
        return result;
    }
}