如何输出一个自定义行列的矩阵？
#include
main()
{
printf("please input n:\n");
scanf("%d");
int a[m][n], i, j, *p1;
p1 = a[0];
printf("please input a:\n");
for (i = 0; i
{
for (j = 0; j
{
scanf("%d", p1++);
}
}
p1 = a[0];
printf("the array is :\n");
for (i = 0; i
{
for (j = 0; j
{
printf("%5d", *p1++);
}
printf("\n");
}
}
------解决思路----------------------
#include "stdafx.h"
#include
#include
#include
int main()
{
int m,n;
printf("please input m and n:\n");
scanf("%d %d",&m,&n);
int i, j;
int *a = (int*)malloc(sizeof(int) * n*m);
printf("please input a:\n");
for (i = 0; i
{
for (j = 0; j
{
scanf("%d", &a[i*m+j]);
}
}
printf("the array is :\n");
for (i = 0; i
{
for (j = 0; j
{
printf("%5d", a[i*m+j]);
}
printf("\n");
}
delete[] a;
getchar();//读取缓冲区遗留的换行符0xA,不会暂停程序
getchar();//暂停程序
}
------解决思路----------------------
把a[m][n]定义放在mn信息采集后。现在C99标准已经支持这种特性喽！gcc支持
示例：
#include
int main(int argc, char *argv[])
{
int m, n;
scanf("%d %d", &m, &n);
int a[m][n];
a[1][2] = 10;
printf("%d\n", a[1][2]);
return 0;
}
------解决思路----------------------
#include
#include
#include
int **newarr2d(int rows,int cols) {
int **p,i;
p=(int **)malloc(rows*sizeof(int *));
if (NULL==p) exit(1);
for (i=0;i
p[i]=(int *)malloc(cols*sizeof(int));
if (NULL==p[i]) exit(1);
}
return p;
}
void deletearr2d(int **p,int rows) {
int i;
for (i=0;i
free(p[i]);
}
free(p);
}
int main() {
int **arr2d,i,j,r,c;
r=4;
c=5;
//在堆中开辟一个4×5的二维int数组
arr2d=newarr2d(r,c);
for (i=0;i
for (j=0;j
arr2d[i][j]=i*c+j;
}
}
for (i=0;i
for (j=0;j
printf(" %2d",arr2d[i][j]);
}
printf("\n");
}
deletearr2d(arr2d,r);
r=6;
c=3;
//在堆中开辟一个6×3的二维int数组
arr2d=newarr2d(r,c);
for (i=0;i
for (j=0;j
arr2d[i][j]=i*c+j;
}
}
for (i=0;i
for (j=0;j
printf(" %2d",arr2d[i][j]);
}
printf("\n");
}
deletearr2d(arr2d,r);
return 0;
}
// 0 1 2 3 4
// 5 6 7 8 9
// 10 11 12 13 14
// 15 16 17 18 19
// 0 1 2
// 3 4 5
// 6 7 8
// 9 10 11
// 12 13 14
// 15 16 17
//