主要特点和优势:
-
声明式编程: 您只需描述您想要的结果,而不是详细说明如何实现这个结果。这使得代码更具可读性和可维护性。
-
函数式编程风格: 可以使用函数式接口和 lambda 表达式来定义对数据的操作。
-
流水线操作: 一系列的中间操作(如
filter
、map
、sorted
等)可以链接在一起,形成一个处理流水线,最后通过终端操作(如collect
、forEach
、reduce
等)产生最终的结果。 -
并行处理: 可以很容易地将顺序流转换为并行流,从而利用多核 CPU 的优势,提高处理大数据集的性能。
List<Person> people = new ArrayList<>();
people.add(new Person("Alice", 25));
people.add(new Person("Bob", 30));
people.add(new Person("Charlie", 28));
// 获取所有人的名字列表
List<String> names = people.stream()
.map(Person::getName)
.collect(Collectors.toList());
System.out.println(names);
List<Person> people = new ArrayList<>();
people.add(new Person("Alice", 25));
people.add(new Person("Bob", 30));
people.add(new Person("Charlie", 28));
// 将 List 转换为 Map
Map<String, Person> personMap = people.stream()
.collect(Collectors.toMap(Person::getName, person -> person));
System.out.println(personMap);
处理合并的
Map<String, Person> personMap = people.stream()
.collect(Collectors.toMap(Person::getName, person -> person, (existingValue, newValue) -> existingValue));
@Test
public void groupTest() {
List<Person> persons = ImmutableList.of(
new Person("Alice", 25),
new Person("Bob", 30),
new Person("Charlie", 25),
new Person("David", 35)
);
// 对对象进行分组
Map<Integer, List<Person>> groupedPersons = persons.stream().collect(Collectors.groupingBy(Person::getAge));
Assert.assertEquals(3, groupedPersons.keySet().size());
}
@Test
public void partitionedTest() {
List<Person> persons = ImmutableList.of(
new Person("Alice", 25),
new Person("Bob", 30),
new Person("Charlie", 25),
new Person("David", 35)
);
Map<Boolean, List<Person>> partitionedPersons = persons.stream().collect(Collectors.partitioningBy(p -> p.getAge() > 30));
Assert.assertEquals(1, partitionedPersons.get(true).size());
}
@Test
public void flattenedTest() {
List<List<String>> names = ImmutableList.of(
ImmutableList.of("Alice", "Bob"),
ImmutableList.of("Charlie", "David")
);
List<String> flattenedNames = names.stream()
.flatMap(List::stream)
.collect(Collectors.toList());
Assert.assertEquals(4, flattenedNames.size());
}
@Test
public void sortedTest() {
List<Person> persons = ImmutableList.of(
new Person("Alice", 25),
new Person("Bob", 30),
new Person("Charlie", 25),
new Person("David", 35)
);
List<Person> sortedPersons = persons.stream()
.sorted(Comparator.comparing(Person::getAge).thenComparing(Person::getName))
.collect(Collectors.toList());
Assert.assertEquals("David", sortedPersons.get(sortedPersons.size() - 1).getName());
}
@Test
public void sortedByLengthTest() {
List<String> words = ImmutableList.of("banana", "cherry", "apple");
List<String> sortedWords = words.stream()
.sorted((s1, s2) -> Integer.compare(s1.length(), s2.length()))
.collect(Collectors.toList());
Assert.assertEquals("apple", sortedWords.get(0));
}
@Test
public void distinctTest() {
List<Integer> list1 = ImmutableList.of(1, 2, 3);
List<Integer> list2 = ImmutableList.of(3, 4, 5);
List<Integer> combinedList = Stream.concat(list1.stream(), list2.stream())
.distinct()
.collect(Collectors.toList());
Assert.assertEquals(5, combinedList.size());
}
@Test
public void filterTest() {
List<String> words = ImmutableList.of("apple", "banana", "cherry");
List<String> longWords = words.stream()
.filter(word -> word.length() > 5)
.collect(Collectors.toList());
Assert.assertEquals(2, longWords.size());
}
@Test
public void maxTest() {
List<Integer> numbers = ImmutableList.of(1, 5, 3, 7, 2);
int max = numbers.stream()
.max(Integer::compareTo)
.orElse(0);
Assert.assertEquals(7, max);
double average = numbers.stream()
.mapToDouble(Integer::doubleValue)
.average()
.orElse(0);
System.out.println(average);
}