使用Markdown记录错误

错误名称：no match for ‘operator<<’ (operand types are ‘std::basic_ostream’ and ‘void’)

插入代码片

博客设置’ 代码片`.

#include<iostream>
using namespace std;
#include<string.h>

class SClass {
	char *p;
public:
	SClass(char *pn) {
		p=new char[strlen(pn)+1];
		strcpy(p,pn);
	}
	~SClass() {
		delete p;
	}
	SClass &operator = (SClass &s){
		delete p;
		p=new char[strlen(s.p)+1];
		strcpy(p,s.p);
		return *this;
	}
	void disp() {
		cout<<p<<endl;
	}
};

int main(){
	SClass s1("first object");
	SClass s2("second object");
	
	cout<<"S1="<<s1.disp()<<endl;
	cout<<"S2="<<s2.disp()<<endl;
	
	cout<<"复制之后："<<endl;
	s2=s1;
	cout<<"S1="<<s1.disp()<<endl;
	cout<<"S2="<<s2.disp()<<endl;
}

总结：
类的成员函数不能直接在cout输出，而应该分成两步走
正确代码如下：

#include<iostream>
using namespace std;
#include<string.h>

class SClass {
	char *p;
public:
	SClass(char *pn) {
		p=new char[strlen(pn)+1];
		strcpy(p,pn);
	}
	~SClass() {
		delete p;
	}
	SClass &operator = (SClass &s){
		delete p;
		p=new char[strlen(s.p)+1];
		strcpy(p,s.p);
		return *this;
	}
	void disp() {
		cout<<p<<endl;
	}
};

int main(){
	SClass s1("first object");
	SClass s2("second object");
	
	cout<<"S1="<<endl;
	s1.disp();
	cout<<"S2="<<endl;
	s2.disp();
	
	cout<<"复制之后："<<endl;
	s2=s1;
	cout<<"S1="<<endl;
	s1.disp();
	cout<<"S2="<<endl;
	s2.disp();
}