SQL练习02 - 悦读

title: SQL练习
time: 2019年8月16日16:09:54
tags: SQL

SQL 练习

查询至少有一门课与学号为“01”的学生所学课程相同的学生的学号和姓名（重点）

SELECT
	s_id,
	s_name 
FROM
	student 
WHERE
	s_id IN (
	SELECT DISTINCT
		s_id 
	FROM
		score 
	WHERE
		c_id IN ( SELECT c_id FROM score WHERE s_id = '01' ) 
	AND s_id != '01' 
	)

查询和“01”号同学所学课程完全相同的其他同学的学号(重点)

SELECT
	s_id 
FROM
	score 
GROUP BY
	s_id 
HAVING
	count( c_id ) = ( SELECT count( c_id ) FROM score WHERE s_id = '01' ) 
	AND s_id != '01'

查询没学过"张三"老师讲授的任一门课程的学生姓名（重点，能做出来）

-- 查询没学过"张三"老师讲授的任一门课程的学生姓名 和47题一样（重点，能做出来）
SELECT
	s_name 
FROM
	student 
WHERE
	s_id NOT IN (
	SELECT
		s_id 
	FROM
		score AS s
		INNER JOIN course AS c ON c.c_id = s.c_id
		INNER JOIN teacher AS t ON t.t_id = c.t_id 
	WHERE
	t_name = '张三' 
	)

查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩（重点）

SELECT
	s.s_id,
	s.s_name,
	a.avg 
FROM
	student AS s
	INNER JOIN ( SELECT s_id, avg( s_score ) AS avg FROM score WHERE s_score < 60 GROUP BY s_id HAVING count( c_id ) >= 2 ) AS a ON s.s_id = a.s_id

检索"01"课程分数小于60，按分数降序排列的学生信息

SELECT
	s.s_id,
	s.s_name,
	s.s_birth,
	s.s_sex,
	a.s_score 
FROM
	student AS s
	INNER JOIN ( SELECT s_id, s_score FROM score WHERE s_score < 60 AND c_id = '01' ORDER BY s_score DESC ) AS a ON s.s_id = a.s_id

检索"01"课程分数小于60，按分数升序排列的学生信息

SELECT
	s.s_id,
	s.s_name,
	s.s_birth,
	s.s_sex,
	a.s_score 
FROM
	student AS s
	INNER JOIN ( SELECT s_id, s_score FROM score WHERE s_score < 60 AND c_id = '01' ORDER BY s_score ASC ) AS a ON s.s_id = a.s_id

按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩(重重点)

-- SQL中的别名 一般不用加双引号和单引号 直接 把别名输入在后边即可，或者加个as
-- 为01，字符值时，也可不用加，如：where name = 李赏 如： where id = 01
SELECT
	s_id 学号,
	max( CASE WHEN c_id = 02 THEN s_score ELSE NULL END )语文,
	min( CASE WHEN c_id = 01 THEN s_score ELSE NULL END ) 数学,
	max( CASE WHEN c_id = 03 THEN s_score ELSE NULL END )英语,
	avg( s_score ) 平均成绩 
FROM
	score 
GROUP BY
	s_id 
ORDER BY
	平均成绩 DESC

查询各科成绩最高分、最低分和平均分：以如下形式显示：课程ID，课程name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率及格为>=60，中等为：70-80，优良为：80-90，优秀为：>=90 (超级重点)

select s.c_id 
, c.c_name
, MAX(s.s_score) 最高分
, MIN(s.s_score) 最低分
, AVG(s.s_score) 平均分
, SUM(case when s.s_score >= 60 then 1 ELSE 0 END) / COUNT(s.s_id) 及格率
, SUM(case when s.s_score >= 70 and s.s_score <80 then 1 ELSE 0 END ) / COUNT(s.s_id) 中等率
, SUM(case when s.s_score >= 80 and s.s_score <90 then 1 ELSE 0 END ) / COUNT(s.s_id) 优良率
, SUM(case when s.s_score >= 90 then 1 ELSE 0 END ) / COUNT(s.s_id) 优秀率

FROM score as s
inner JOIN course as c 
on s.c_id = c.c_id
GROUP BY c_id

按各科成绩进行排序，并显示排名(重点row_number)

-- rank() over (partition by ..(按什么分组)(每一组都是从1开始的) order by ..(按什么排序))
		--> 跳跃式 排序，如：第二名第三名成绩一样，他们排名都是2， 第三名下个直接是4
-- dense_rank() over (partition by ..(按什么分组) order by ..(按什么排序))
		--> 连续 排序，如：第二名第三名成绩一样，他们排名都是2， 第三名下个直接是3
-- row_number() over (partition by ..(按什么分组) order by ..(按什么排序))
		--> 连续 排序，如：第二名第三名成绩一样，第一个排名是2另一个排名3，， 第三名下个直接是4
		
SELECT
	s_id,
	c_id,
	s_score,
	ROW_number () over ( PARTITION BY c_id ORDER BY s_score DESC ) AS rank 
FROM
	score

查询学生的总成绩并进行排名（不重点）

SELECT
	s_id,
	SUM( s_score ) AS 总成绩 
FROM
	score 
GROUP BY
	s_id 
ORDER BY
	总成绩 DESC

查询不同老师所教不同课程平均分从高到低显示(不重点)

SELECT
	c_id,
	AVG( s_score ) 
FROM
	score 
GROUP BY
	c_id DESC

查询所有课程的成绩第2名到第3名的学生信息及该课程成绩（重要 )

SELECT
	s.s_id,
	st.s_name,
	st.s_sex,
	st.s_birth,
	s.c_id,
	s.s_score,
	row_number over ( PARTITION BY c_id ORDER BY s_score DESC ) rank 
FROM
	score AS s
	INNER JOIN student AS st ON st.s_id = s.s_id 
WHERE
	s.rank IN ( 2, 3 )

使用分段[100-85],[85-70],[70-60],[<60]来统计各科成绩，分别统计各分数段人数：课程ID和课程名称

SELECT
	s.c_id,
	c.c_name,
	sum( CASE WHEN s.s_score <= 100 AND s.s_score > 85 THEN 1 ELSE 0 END ) '[100 , 85)',
	count( CASE WHEN s.s_score <= 85 AND s.s_score > 70 THEN 1 ELSE NULL END ) '[85 , 70)',
	sum( CASE WHEN s.s_score <= 70 AND s.s_score > 60 THEN 1 ELSE 0 END ) '[70 , 60)',
	sum( CASE WHEN s.s_score < 60 THEN 1 ELSE 0 END ) '<60' 
FROM
	score AS s
	INNER JOIN course AS c ON s.c_id = c.c_id 
GROUP BY
	s.c_id

查询学生平均成绩及其名次（重点）

SELECT
	s_id,
	AVG( s_score ) AS avg,
	row_number () over ( ORDER BY avg DESC ) 
FROM
	score 
GROUP BY
	s_id

查询各科成绩前三名的记录（不考虑成绩并列情况）（重点）

SELECT
	c_id,
	row_number () over ( PARTITION BY c_id ORDER BY s_score DESC ) AS rank 
FROM
	score 
WHERE
	rank IN ( 1, 2, 3 )

查询每门课程被选修的学生数(不重点)

SELECT
	c_id,
	count( s_id ) 
FROM
	score 
GROUP BY
	c_id

查询出只有两门课程的全部学生的学号和姓名(不重点)

-- GROUP BY 不能加where 筛选
-- 只能有having进行筛选

-- GROUP BY .. having.. 必须在表连接之后进行操作
SELECT
	s.s_id,
	st.s_name,
	count( s.s_id ) AS cid 
FROM
	score AS s
	INNER JOIN student AS st ON st.s_id = s.s_id 
GROUP BY
	s.s_id 
HAVING
	cid = 2

hving进行筛选

-- GROUP BY .. having.. 必须在表连接之后进行操作
SELECT
	s.s_id,
	st.s_name,
	count( s.s_id ) AS cid 
FROM
	score AS s
	INNER JOIN student AS st ON st.s_id = s.s_id 
GROUP BY
	s.s_id 
HAVING
	cid = 2