1、

import re

# 将正则表达式编译成Pattern对象
pattern = re.compile(r'hello',re.I)

# 使用Pattern匹配文本，获得匹配结果，无法匹配时将返回None
match = pattern.match('hello world!')

if match:
# 使用Match获得分组信息
print match.group()

2、

import re
m = re.match(r'(\w+) (\w+)(?P<sign>.*)', 'hello world!')

print "m.string:", m.string
print "m.re:", m.re
print "m.pos:", m.pos
print "m.endpos:", m.endpos
print "m.lastindex:", m.lastindex
print "m.lastgroup:", m.lastgroup

print "m.group(1,2):", m.group(1, 2)
print "m.groups():", m.groups()
print "m.groupdict():", m.groupdict()
print "m.start(2):", m.start(2)
print "m.end(2):", m.end(2)
print "m.span(2):", m.span(2)
print r"m.expand(r'\2 \1\3'):", m.expand(r'\2 \1\3')

### output ###
# m.string: hello world!
# m.re: <_sre.SRE_Pattern object at 0x016E1A38>
# m.pos: 0
# m.endpos: 12
# m.lastindex: 3
# m.lastgroup: sign
# m.group(1,2): ('hello', 'world')
# m.groups(): ('hello', 'world', '!')
# m.groupdict(): {'sign': '!'}
# m.start(2): 6
# m.end(2): 11
# m.span(2): (6, 11)
# m.expand(r'\2 \1\3'): world hello!

3、

# 使用search()查找匹配的子串，不存在能匹配的子串时将返回None
# 这个例子中使用match()无法成功匹配
match = pattern.search('hello world!')

4、

p = re.compile(r'\d+')
print p.split('one1two2three3four4')

### output ###
# ['one', 'two', 'three', 'four', '']

5、

p = re.compile(r'\d+')
print p.findall('one1two2three3four4')

### output ###
# ['1', '2', '3', '4']

6、

p = re.compile(r'\d+')
for m in p.finditer('one1two2three3four4'):
print m.group(),

### output ###
# 1 2 3 4

7、

p = re.compile(r'(\w+) (\w+)')
s = 'i say, hello world!'

print p.sub(r'\2 \1', s)

def func(m):
return m.group(1).title() + ' ' + m.group(2).title()

print p.sub(func, s)

### output ###
# say i, world hello!
# I Say, Hello World!

8、返回 (sub(repl, string[, count]), 替换次数)

p = re.compile(r'(\w+) (\w+)')
s = 'i say, hello world!'

print p.subn(r'\2 \1', s)

def func(m):
return m.group(1).title() + ' ' + m.group(2).title()

print p.subn(func, s)

### output ###
# ('say i, world hello!', 2)
# ('I Say, Hello World!', 2)