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JS计算小数加减乘除精确算法

js 两个小数相加,返回精确值

  accAdd(data1, data2) {
    var r1, r2, m, c;
    try {  r1 = data1.toString().split(".")[1].length;}catch (e) {  r1 = 0; }
    try { r2 = data2.toString().split(".")[1].length; } catch (e) { r2 = 0; }
    c = Math.abs(r1 - r2);
    m = Math.pow(10, Math.max(r1, r2));
    if (c > 0) {
        var cm = Math.pow(10, c);
        if (r1 > r2) {
            data1= Number(data1.toString().replace(".", ""));
            data2= Number(data2.toString().replace(".", "")) * cm;
        } else {
            data1= Number(data1.toString().replace(".", "")) * cm;
            data2= Number(data2.toString().replace(".", ""));
        }
    } else {
        data1= Number(data1.toString().replace(".", ""));
        data2= Number(data2.toString().replace(".", ""));
    }
    return (data1+ data2) / m;
}

js 两个小数相减

numSub(data1, data2) {
  var num, num1, num2;
  var precision;// 精度
  try {  num1 = data1.toString().split(".")[1].length; } catch (e) {  num1 = 0; }
  try { num2 = data2.toString().split(".")[1].length; } catch (e) {  num2 = 0;  }
  num = Math.pow(10, Math.max(num1, num2));
  precision = (num1 >= num2) ? num1 : num2;
  return ((data1* num - data1* num) / num).toFixed(precision);
};

js两个小数相乘

 accMulti(data1, data2) {
  var baseData = 0;
  try { baseData += data1.toString().split(".")[1].length;} catch (e) {}
  try { baseData += data2.toString().split(".")[1].length;} catch (e) {}
  return Number(data1.toString().replace(".", "")) * Number(data2.toString().replace(".", "")) / Math.pow(10, baseData);
}

js两个小数相除

这个是没有保留位数的

function division(arg1, arg2){
var t1 = 0, t2 = 0, r1, r2;
try {
t1 = new String(arg1).split(".")[1].length;
} catch (e) { }
try {
t2 = arg2.toString().split(".")[1].length;
} catch (e) { }
r1 = Number(arg1.toString().replace(".", ""));
r2 = Number(arg2.toString().replace(".", ""));
//放大倍数后两个数相除 后,乘以两个小数位数长度相减后的10的次幂
var newData= accMulti((r1 / r2),Math.pow(10, t2 - t1));
//保留2个小数位数:return newData.toFixed(2)
return newData;
}

alert(division(1.732,1.4146)=1.224374381450587

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